\(10a^2+11a-6\) को गुणनखंडित कीजिए।

Factorise \(10a^2+11a-6\).

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((5a-2)(2a+3))

Step 1

Concept

((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).

Step 2

Why this answer is correct

The correct answer is A. ((5a-2)(2a+3)). ((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).

Step 3

Exam Tip

((5a-2)(2a+3)) से \(10a^2+15a-4a-6\) मिलता है। परीक्षा में मध्य पद (11a) की पुष्टि करें।

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Mathematics Answer, Explanation and Revision Hints

\(10a^2+11a-6\) को गुणनखंडित कीजिए। / Factorise \(10a^2+11a-6\).

Correct Answer: A. ((5a-2)(2a+3)). Explanation: ((5a-2)(2a+3)) से \(10a^2+15a-4a-6\) मिलता है। परीक्षा में मध्य पद (11a) की पुष्टि करें। / ((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).

Which concept should I revise for this Mathematics MCQ?

((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).

What exam hint can help solve this Mathematics question?

((5a-2)(2a+3)) से \(10a^2+15a-4a-6\) मिलता है। परीक्षा में मध्य पद (11a) की पुष्टि करें।