\(10a^2+11a-6\) को गुणनखंडित कीजिए।
Factorise \(10a^2+11a-6\).
Explanation opens after your attempt
A. ((5a-2)(2a+3))
Concept
((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).
Why this answer is correct
The correct answer is A. ((5a-2)(2a+3)). ((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).
Exam Tip
((5a-2)(2a+3)) से \(10a^2+15a-4a-6\) मिलता है। परीक्षा में मध्य पद (11a) की पुष्टि करें।
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