\(x^2+7x+12-y^2\) का गुणनखंड रूप चुनिए।
Choose the factorised form of \(x^2+7x+12-y^2\).
Explanation opens after your attempt
Correct Answer
C. ( (x+3-y)(x+4+y) )
Concept
Factoring \(x^2+7x+12\) as ((x+3)(x+4)) alone is not enough. Expanding the given option also gives the term \(-y^2\).
Why this answer is correct
The correct answer is C. ( (x+3-y)(x+4+y) ). Factoring \(x^2+7x+12\) as ((x+3)(x+4)) alone is not enough. Expanding the given option also gives the term \(-y^2\).
Exam Tip
\(x^2+7x+12\) को ((x+3)(x+4)) तोड़ना पर्याप्त नहीं है। दिए गए विकल्प को फैलाने पर सही पद \( -y^2 \) भी मिलता है।
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