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Between which two integers does ( \sqrt{10} ) lie?

Answer and explanation

Correct answer: (3) and (4)

Direct answer: Option C, between 3 and 4. To locate a square root, compare the number under the root with nearby perfect squares. We have \(3^2=9\) and \(4^2=16\). Since \(9<10<16\), taking square roots gives \(3<\sqrt{10}<4\), because square root is increasing for non-negative numbers. Therefore \(\sqrt{10}\) lies between 3 and 4. Option A, between 1 and 2, is wrong because the squares of 1 and 2 are 1 and 4, and 10 is not between them. Option B, between 2 and 3, is wrong because 10 is greater than \(3^2=9\), so its square root is greater than 3. Option C is correct because 10 lies between \(3^2\) and \(4^2\). Option D, between 4 and 5, is wrong because \(10<16=4^2\), so the root must be less than 4. Remember: bracket a square root by finding the two consecutive perfect squares around the radicand.

Related tags

Real NumbersClass 9Estimation

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