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Before assuming \(\sqrt{3}=\frac{p}{q}\) in a proof by contradiction that \(\sqrt{3}\) is irrational, which condition on \(p\) and \(q\) is essential?

Answer and explanation

Correct answer: \(p\) and \(q\) are coprime

Writing the fraction in lowest terms makes \(p\) and \(q\) coprime. From \(p^2=3q^2\), 3 divides \(p\), and then \(q\), creating a contradiction. Exam tip: state “lowest terms” explicitly.

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof By ContradictionCoprime IntegersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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