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A student says that the decimal expansion of every irrational number is non-terminating and recurring. Why is this statement incorrect?

Answer and explanation

Correct answer: The decimal expansion of irrational numbers is non-terminating and non-recurring.

The decimal expansion of an irrational number is non-terminating, but no fixed block of digits repeats indefinitely; hence it is non-recurring. For example, \(\sqrt{2}=1.414213\ldots\) is non-terminating and non-recurring. In contrast, \(1/3=0.333\ldots\) is non-terminating and recurring, so it is rational. Exam tip: recurring decimals are rational, while non-terminating non-recurring decimals are irrational.

Related tags

Real NumbersIrrational NumbersDecimal ExpansionRecurring DecimalsNumber SystemsMathematicsClass 9 Mcq

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