\(\sin^{-1}(\sin\theta)=\theta\) कब निश्चित रूप से सत्य है?

When is \(\sin^{-1}(\sin\theta)=\theta\) definitely true?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

B. \(\theta\in[-\frac{\pi}{2},\frac{\pi}{2}]\)

Step 1

Concept

The output of \(\sin^{-1}x\) lies in \([-\frac{\pi}{2},\frac{\pi}{2}]\). Therefore \(\theta\) must lie in this range.

Step 2

Why this answer is correct

The correct answer is B. \(\theta\in[-\frac{\pi}{2},\frac{\pi}{2}]\). The output of \(\sin^{-1}x\) lies in \([-\frac{\pi}{2},\frac{\pi}{2}]\). Therefore \(\theta\) must lie in this range.

Step 3

Exam Tip

\(\sin^{-1}x\) का आउटपुट \([-\frac{\pi}{2},\frac{\pi}{2}]\) में होता है। इसलिए \(\theta\) इसी range में होना चाहिए।

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Mathematics Answer, Explanation and Revision Hints

\(\sin^{-1}(\sin\theta)=\theta\) कब निश्चित रूप से सत्य है? / When is \(\sin^{-1}(\sin\theta)=\theta\) definitely true?

Correct Answer: B. \(\theta\in[-\frac{\pi}{2},\frac{\pi}{2}]\). Explanation: \(\sin^{-1}x\) का आउटपुट \([-\frac{\pi}{2},\frac{\pi}{2}]\) में होता है। इसलिए \(\theta\) इसी range में होना चाहिए। / The output of \(\sin^{-1}x\) lies in \([-\frac{\pi}{2},\frac{\pi}{2}]\). Therefore \(\theta\) must lie in this range.

Which concept should I revise for this Mathematics MCQ?

The output of \(\sin^{-1}x\) lies in \([-\frac{\pi}{2},\frac{\pi}{2}]\). Therefore \(\theta\) must lie in this range.

What exam hint can help solve this Mathematics question?

\(\sin^{-1}x\) का आउटपुट \([-\frac{\pi}{2},\frac{\pi}{2}]\) में होता है। इसलिए \(\theta\) इसी range में होना चाहिए।