\(यदि (U={1,2,\ldots,48}), (A={x:x\) 4 का गुणज है\(}) और (B={x:x\) 8 का गुणज है\(}), तो (A'\cap B') किसके बराबर है\)?
\(If (U={1,2,\ldots,48}), (A={x:x\) is a multiple of \(4}) and (B={x:x\) is a multiple of \(8}), what is (A'\cap B') equal to\)?
Explanation opens after your attempt
Correct Answer
A. (A')
Concept
Since \(B\subseteq A\), \(A\cup B=A\). Hence (A'\cap B'=\(A\cup B\)'=A').
Why this answer is correct
The correct answer is A. (A'). Since \(B\subseteq A\), \(A\cup B=A\). Hence (A'\cap B'=\(A\cup B\)'=A').
Exam Tip
क्योंकि \(B\subseteq A\), इसलिए \(A\cup B=A\)। अतः (A'\cap B'=\(A\cup B\)'=A') होगा।
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