यदि (n(A)=48), (n(B)=43), (n(C)=41), (n\(A\cup B\cup C\)=99), (n\(A\cap B\)=17), (n\(B\cap C\)=14) और (n\(C\cap A\)=13) है, तो (n\(A\cap B\cap C\)) कितना है?
If (n(A)=48), (n(B)=43), (n(C)=41), (n\(A\cup B\cup C\)=99), (n\(A\cap B\)=17), (n\(B\cap C\)=14), and (n\(C\cap A\)=13), what is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
D. (11)
Concept
In the formula (99=48+43+41-17-14-13+x), so (x=11). Find the unknown central part by forming an equation.
Why this answer is correct
The correct answer is D. (11). In the formula (99=48+43+41-17-14-13+x), so (x=11). Find the unknown central part by forming an equation.
Exam Tip
सूत्र में (99=48+43+41-17-14-13+x) होगा, इसलिए (x=11)। अज्ञात केंद्रीय भाग को समीकरण से निकालें।
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