यदि (n(A)=46), (n(B)=40), (n(C)=37), (n\(A\cap B\)=14), (n\(B\cap C\)=12), (n\(C\cap A\)=11) और (n\(A\cup B\cup C\)=91) है, तो (n\(A\cap B\cap C\)) कितना है?
If (n(A)=46), (n(B)=40), (n(C)=37), (n\(A\cap B\)=14), (n\(B\cap C\)=12), (n\(C\cap A\)=11), and (n\(A\cup B\cup C\)=91), what is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
B. (5)
Concept
In the formula (91=46+40+37-14-12-11+x), so (x=5). In three sets, the central part is added at the end.
Why this answer is correct
The correct answer is B. (5). In the formula (91=46+40+37-14-12-11+x), so (x=5). In three sets, the central part is added at the end.
Exam Tip
सूत्र में (91=46+40+37-14-12-11+x) होगा, इसलिए (x=5)। तीन समुच्चयों में केंद्रीय भाग अंत में जोड़ा जाता है।
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