युग्म असमानता \(1<\frac{x-2}{3}\leq4\) का हल क्या है?
What is the solution of \(1<\frac{x-2}{3}\leq4\)?
Explanation opens after your attempt
Correct Answer
A. \(5<x\leq14\)
Concept
Multiplying by (3) gives \(3<x-2\leq12\) and then \(5<x\leq14\). A positive multiplier does not change the signs.
Why this answer is correct
The correct answer is A. \(5<x\leq14\). Multiplying by (3) gives \(3<x-2\leq12\) and then \(5<x\leq14\). A positive multiplier does not change the signs.
Exam Tip
(3) से गुणा करने पर \(3<x-2\leq12\) और फिर \(5<x\leq14\) मिलता है। धन गुणक से चिन्ह नहीं बदलता।
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