फलन (f(x)=\sqrt{9-(x-1)2}) का प्रांत क्या है?
What is the domain of (f(x)=\sqrt{9-(x-1)2})?
Explanation opens after your attempt
Correct Answer
A. ([-2,4])
Concept
The condition (9-(x-1)2\ge 0) gives ((x-1)2\le 9). Hence \(x\in[-2,4]\).
Why this answer is correct
The correct answer is A. ([-2,4]). The condition (9-(x-1)2\ge 0) gives ((x-1)2\le 9). Hence \(x\in[-2,4]\).
Exam Tip
शर्त (9-(x-1)2\ge 0) से ((x-1)2\le 9) मिलता है। इसलिए \(x\in[-2,4]\)।
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