असमानता \(2x+y \le 6\) में \(y \ge 0\) भी हो तो (x)-अक्ष पर समाधान खंड क्या होगा?
If \(y \ge 0\) is also included with \(2x+y \le 6\), what is the solution segment on the (x)-axis?
Explanation opens after your attempt
Correct Answer
A. \(x \le 3\)
Concept
On the (x)-axis, (y=0), so \(2x \le 6\) and \(x \le 3\). If \(x \ge 0\) is not separately given, negative (x)-values may also be included.
Why this answer is correct
The correct answer is A. \(x \le 3\). On the (x)-axis, (y=0), so \(2x \le 6\) and \(x \le 3\). If \(x \ge 0\) is not separately given, negative (x)-values may also be included.
Exam Tip
(x)-अक्ष पर (y=0), इसलिए \(2x \le 6\) और \(x \le 3\)। यदि \(x \ge 0\) अलग से न दिया हो तो ऋणात्मक (x) भी शामिल हो सकते हैं।
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