यदि \(U={x:x\in \mathbb{Z},-2\le x\le 2}\) और \(A={x:x\in U,x^2=1}\), तो (n(P(A'))) क्या है?
If \(U={x:x\in \mathbb{Z},-2\le x\le 2}\) and \(A={x:x\in U,x^2=1}\), then what is (n(P(A')))?
Explanation opens after your attempt
B. (8)
Concept
\(U=\{-2,-1,0,1,2\}\) and \(A=\{-1,1\}\), so (A'={-2,0,2}). Thus (n(P(A'))=23=8).
Why this answer is correct
The correct answer is B. (8). \(U=\{-2,-1,0,1,2\}\) and \(A=\{-1,1\}\), so (A'={-2,0,2}). Thus (n(P(A'))=23=8).
Exam Tip
\(U=\{-2,-1,0,1,2\}\) और \(A=\{-1,1\}\), इसलिए (A'={-2,0,2})। अब (n(P(A'))=23=8)।
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