यदि \(U={x:x\in \mathbb{Z},-2\le x\le 2}\) और \(A={x:x\in U,x^2=1}\), तो (n(P(A'))) क्या है?

If \(U={x:x\in \mathbb{Z},-2\le x\le 2}\) and \(A={x:x\in U,x^2=1}\), then what is (n(P(A')))?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

\(U=\{-2,-1,0,1,2\}\) and \(A=\{-1,1\}\), so (A'={-2,0,2}). Thus (n(P(A'))=23=8).

Step 2

Why this answer is correct

The correct answer is B. (8). \(U=\{-2,-1,0,1,2\}\) and \(A=\{-1,1\}\), so (A'={-2,0,2}). Thus (n(P(A'))=23=8).

Step 3

Exam Tip

\(U=\{-2,-1,0,1,2\}\) और \(A=\{-1,1\}\), इसलिए (A'={-2,0,2})। अब (n(P(A'))=23=8)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x\in \mathbb{Z},-2\le x\le 2}\) और \(A={x:x\in U,x^2=1}\), तो (n(P(A'))) क्या है? / If \(U={x:x\in \mathbb{Z},-2\le x\le 2}\) and \(A={x:x\in U,x^2=1}\), then what is (n(P(A')))?

Correct Answer: B. (8). Explanation: \(U=\{-2,-1,0,1,2\}\) और \(A=\{-1,1\}\), इसलिए (A'={-2,0,2})। अब (n(P(A'))=23=8)। / \(U=\{-2,-1,0,1,2\}\) and \(A=\{-1,1\}\), so (A'={-2,0,2}). Thus (n(P(A'))=23=8).

Which concept should I revise for this Mathematics MCQ?

\(U=\{-2,-1,0,1,2\}\) and \(A=\{-1,1\}\), so (A'={-2,0,2}). Thus (n(P(A'))=23=8).

What exam hint can help solve this Mathematics question?

\(U=\{-2,-1,0,1,2\}\) और \(A=\{-1,1\}\), इसलिए (A'={-2,0,2})। अब (n(P(A'))=23=8)।