Class 11 Mathematics Sets Complement of a Set and its properties Hard Level 21

यदि \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12\}\) और \(B=\{6,9,12,15,18\}\), तो ((B-A)') क्या है?

If \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12\}\) and \(B=\{6,9,12,15,18\}\), what is ((B-A)')?

Explanation opens after your attempt
Correct Answer

A. ({1,2,3,4,5,6,7,8,10,11,12,13,14,16,17})

Step 1

Concept

(B-A={9,15,18}), so its complement is (U-{9,15,18}). Option (A) gives exactly that set.

Step 2

Why this answer is correct

The correct answer is A. ({1,2,3,4,5,6,7,8,10,11,12,13,14,16,17}). (B-A={9,15,18}), so its complement is (U-{9,15,18}). Option (A) gives exactly that set.

Step 3

Exam Tip

(B-A={9,15,18}), इसलिए इसका पूरक (U-{9,15,18}) है। विकल्प (A) वही समुच्चय देता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12\}\) और \(B=\{6,9,12,15,18\}\), तो ((B-A)') क्या है? / If \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12\}\) and \(B=\{6,9,12,15,18\}\), what is ((B-A)')?

Correct Answer: A. ({1,2,3,4,5,6,7,8,10,11,12,13,14,16,17}). Explanation: (B-A={9,15,18}), इसलिए इसका पूरक (U-{9,15,18}) है। विकल्प (A) वही समुच्चय देता है। / (B-A={9,15,18}), so its complement is (U-{9,15,18}). Option (A) gives exactly that set.

Which concept should I revise for this Mathematics MCQ?

(B-A={9,15,18}), so its complement is (U-{9,15,18}). Option (A) gives exactly that set.

What exam hint can help solve this Mathematics question?

(B-A={9,15,18}), इसलिए इसका पूरक (U-{9,15,18}) है। विकल्प (A) वही समुच्चय देता है।