यदि सीमा रेखा (x-3y=6) ठोस है और छायांकन उस ओर है जहाँ ((0,-3)) है तो सही असमानता कौन सी है?
If the boundary line (x-3y=6) is solid and shading is on the side containing ((0,-3)), which inequality is correct?
Explanation opens after your attempt
Correct Answer
C. \(x-3y \ge 6\)
Concept
Substituting ((0,-3)) gives (0-3(-3)=9), so \(9 \ge 6\) is true and \(\ge\) is correct for a solid line. Combine the test point with line type.
Why this answer is correct
The correct answer is C. \(x-3y \ge 6\). Substituting ((0,-3)) gives (0-3(-3)=9), so \(9 \ge 6\) is true and \(\ge\) is correct for a solid line. Combine the test point with line type.
Exam Tip
((0,-3)) रखने पर (0-3(-3)=9), इसलिए \(9 \ge 6\) सत्य है और ठोस रेखा के लिए \(\ge\) सही है। परीक्षण बिंदु और रेखा का प्रकार साथ मिलाएं।
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