यदि \(\sin^2 x=\frac{1}{4}\) और (x) प्रथम चतुर्थांश में है, तो \(\cos x\) का मान क्या है?
If \(\sin^2 x=\frac{1}{4}\) and (x) is in the first quadrant, what is the value of \(\cos x\)?
Explanation opens after your attempt
Correct Answer
C. \(\frac{\sqrt{3}}{2}\)
Concept
\(\cos^2 x=1-\frac{1}{4}=\frac{3}{4}\). In the first quadrant, \(\cos x=\frac{\sqrt{3}}{2}\) is taken.
Why this answer is correct
The correct answer is C. \(\frac{\sqrt{3}}{2}\). \(\cos^2 x=1-\frac{1}{4}=\frac{3}{4}\). In the first quadrant, \(\cos x=\frac{\sqrt{3}}{2}\) is taken.
Exam Tip
\(\cos^2 x=1-\frac{1}{4}=\frac{3}{4}\) होगा। प्रथम चतुर्थांश में \(\cos x=\frac{\sqrt{3}}{2}\) लिया जाता है।
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