यदि (n(A)=70), (n(B)=65), (n(C)=60), (n\(A\cup B\cup C\)=140), (n\(A\cap B\)=28), (n\(B\cap C\)=24) और (n\(C\cap A\)=22) है, तो (n\(A\cap B\cap C\)) कितना है?
If (n(A)=70), (n(B)=65), (n(C)=60), (n\(A\cup B\cup C\)=140), (n\(A\cap B\)=28), (n\(B\cap C\)=24), and (n\(C\cap A\)=22), what is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
C. (19)
Concept
In the formula (140=70+65+60-28-24-22+x), so (x=19). For the central part, write inclusion-exclusion as an equation.
Why this answer is correct
The correct answer is C. (19). In the formula (140=70+65+60-28-24-22+x), so (x=19). For the central part, write inclusion-exclusion as an equation.
Exam Tip
सूत्र में (140=70+65+60-28-24-22+x) होगा, इसलिए (x=19)। केंद्रीय भाग के लिए समावेशन-बहिष्करण को समीकरण की तरह लिखें।
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