यदि (n(A)=40), (n(B)=36), (n(C)=34), (n\(A\cup B\cup C\)=82), (n\(A\cap B\)=12), (n\(B\cap C\)=10) और (n\(C\cap A\)=9) है, तो (n\(A\cap B\cap C\)) कितना है?
If (n(A)=40), (n(B)=36), (n(C)=34), (n\(A\cup B\cup C\)=82), (n\(A\cap B\)=12), (n\(B\cap C\)=10), and (n\(C\cap A\)=9), what is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
A. (3)
Concept
In the formula (82=40+36+34-12-10-9+x), so (x=3). Find the unknown central part by forming an equation.
Why this answer is correct
The correct answer is A. (3). In the formula (82=40+36+34-12-10-9+x), so (x=3). Find the unknown central part by forming an equation.
Exam Tip
सूत्र में (82=40+36+34-12-10-9+x) होगा, इसलिए (x=3)। अज्ञात केंद्रीय भाग को समीकरण से निकालें।
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