यदि \(A={x:x\in\mathbb{N},3\le x\le8}\) और \(B={y:y\in\mathbb{N},y\le4}\) हैं, तो \(|A\times B|\) क्या है?

If \(A={x:x\in\mathbb{N},3\le x\le8}\) and \(B={y:y\in\mathbb{N},y\le4}\), what is \(|A\times B|\)?

Explanation opens after your attempt
Correct Answer

C. (24)

Step 1

Concept

Here (|A|=6) and (|B|=4), so \(|A\times B|=6\cdot4=24\). Count the elements first.

Step 2

Why this answer is correct

The correct answer is C. (24). Here (|A|=6) and (|B|=4), so \(|A\times B|=6\cdot4=24\). Count the elements first.

Step 3

Exam Tip

यहाँ (|A|=6) और (|B|=4), इसलिए \(|A\times B|=6\cdot4=24\)। पहले समुच्चयों के अवयव गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in\mathbb{N},3\le x\le8}\) और \(B={y:y\in\mathbb{N},y\le4}\) हैं, तो \(|A\times B|\) क्या है? / If \(A={x:x\in\mathbb{N},3\le x\le8}\) and \(B={y:y\in\mathbb{N},y\le4}\), what is \(|A\times B|\)?

Correct Answer: C. (24). Explanation: यहाँ (|A|=6) और (|B|=4), इसलिए \(|A\times B|=6\cdot4=24\)। पहले समुच्चयों के अवयव गिनें। / Here (|A|=6) and (|B|=4), so \(|A\times B|=6\cdot4=24\). Count the elements first.

Which concept should I revise for this Mathematics MCQ?

Here (|A|=6) and (|B|=4), so \(|A\times B|=6\cdot4=24\). Count the elements first.

What exam hint can help solve this Mathematics question?

यहाँ (|A|=6) और (|B|=4), इसलिए \(|A\times B|=6\cdot4=24\)। पहले समुच्चयों के अवयव गिनें।