यदि \(A\cap B=\varnothing\), (n(A)=15) और (n(B)=19), तो (n\(A\cup B\)) क्या है?

If \(A\cap B=\varnothing\), (n(A)=15), and (n(B)=19), what is (n\(A\cup B\))?

Explanation opens after your attempt
Correct Answer

A. (34)

Step 1

Concept

Disjoint sets have no common element. Hence (n\(A\cup B\)=15+19=34).

Step 2

Why this answer is correct

The correct answer is A. (34). Disjoint sets have no common element. Hence (n\(A\cup B\)=15+19=34).

Step 3

Exam Tip

असंबद्ध समुच्चयों में कोई सामान्य तत्व नहीं होता। इसलिए (n\(A\cup B\)=15+19=34)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A\cap B=\varnothing\), (n(A)=15) और (n(B)=19), तो (n\(A\cup B\)) क्या है? / If \(A\cap B=\varnothing\), (n(A)=15), and (n(B)=19), what is (n\(A\cup B\))?

Correct Answer: A. (34). Explanation: असंबद्ध समुच्चयों में कोई सामान्य तत्व नहीं होता। इसलिए (n\(A\cup B\)=15+19=34)। / Disjoint sets have no common element. Hence (n\(A\cup B\)=15+19=34).

Which concept should I revise for this Mathematics MCQ?

Disjoint sets have no common element. Hence (n\(A\cup B\)=15+19=34).

What exam hint can help solve this Mathematics question?

असंबद्ध समुच्चयों में कोई सामान्य तत्व नहीं होता। इसलिए (n\(A\cup B\)=15+19=34)।