असमानताओं \(x\leq 5\), \(y\leq 3\), \(x+y\geq 4\), \(x\geq 0\), \(y\geq 0\) के हल-क्षेत्र में कितने शीर्ष हैं?

How many vertices are in the solution region of \(x\leq 5\), \(y\leq 3\), \(x+y\geq 4\), \(x\geq 0\), and \(y\geq 0\)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

Inside the rectangle, the part above (x+y=4) remains. Its vertices are ((1,3)), ((5,3)), ((5,0)), and ((4,0)).

Step 2

Why this answer is correct

The correct answer is B. (4). Inside the rectangle, the part above (x+y=4) remains. Its vertices are ((1,3)), ((5,3)), ((5,0)), and ((4,0)).

Step 3

Exam Tip

आयत में रेखा (x+y=4) के ऊपर का भाग बचता है। इसके शीर्ष ((1,3)), ((5,3)), ((5,0)), ((4,0)) हैं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x\leq 5\), \(y\leq 3\), \(x+y\geq 4\), \(x\geq 0\), \(y\geq 0\) के हल-क्षेत्र में कितने शीर्ष हैं? / How many vertices are in the solution region of \(x\leq 5\), \(y\leq 3\), \(x+y\geq 4\), \(x\geq 0\), and \(y\geq 0\)?

Correct Answer: B. (4). Explanation: आयत में रेखा (x+y=4) के ऊपर का भाग बचता है। इसके शीर्ष ((1,3)), ((5,3)), ((5,0)), ((4,0)) हैं। / Inside the rectangle, the part above (x+y=4) remains. Its vertices are ((1,3)), ((5,3)), ((5,0)), and ((4,0)).

Which concept should I revise for this Mathematics MCQ?

Inside the rectangle, the part above (x+y=4) remains. Its vertices are ((1,3)), ((5,3)), ((5,0)), and ((4,0)).

What exam hint can help solve this Mathematics question?

आयत में रेखा (x+y=4) के ऊपर का भाग बचता है। इसके शीर्ष ((1,3)), ((5,3)), ((5,0)), ((4,0)) हैं।