Concept-wise Practice

rectangle clipping MCQ Questions for Class 11

rectangle clipping se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with rectangle clipping.

असमानताओं \(x\geq 2\), \(y\geq 1\), \(x\leq 6\), \(y\leq 5\), \(x+y\leq 8\) के हल-क्षेत्र में कितने शीर्ष हैं?

How many vertices are in the solution region of \(x\geq 2\), \(y\geq 1\), \(x\leq 6\), \(y\leq 5\), and \(x+y\leq 8\)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The rectangle \([2,6]\times[1,5]\) is cut by the line (x+y=8). The corners are ((2,1)), ((6,1)), ((6,2)), ((3,5)), and ((2,5)).

Step 2

Why this answer is correct

The correct answer is C. (5). The rectangle \([2,6]\times[1,5]\) is cut by the line (x+y=8). The corners are ((2,1)), ((6,1)), ((6,2)), ((3,5)), and ((2,5)).

Step 3

Exam Tip

आयत \([2,6]\times[1,5]\) को रेखा (x+y=8) काटती है। कोने ((2,1)), ((6,1)), ((6,2)), ((3,5)), ((2,5)) हैं।

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असमानताओं \(x\leq 5\), \(y\leq 3\), \(x+y\geq 4\), \(x\geq 0\), \(y\geq 0\) के हल-क्षेत्र में कितने शीर्ष हैं?

How many vertices are in the solution region of \(x\leq 5\), \(y\leq 3\), \(x+y\geq 4\), \(x\geq 0\), and \(y\geq 0\)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

Inside the rectangle, the part above (x+y=4) remains. Its vertices are ((1,3)), ((5,3)), ((5,0)), and ((4,0)).

Step 2

Why this answer is correct

The correct answer is B. (4). Inside the rectangle, the part above (x+y=4) remains. Its vertices are ((1,3)), ((5,3)), ((5,0)), and ((4,0)).

Step 3

Exam Tip

आयत में रेखा (x+y=4) के ऊपर का भाग बचता है। इसके शीर्ष ((1,3)), ((5,3)), ((5,0)), ((4,0)) हैं।

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असमानताओं \(x\leq 6\), \(y\leq 4\), \(x+2y\geq 10\), \(x\geq 0\), \(y\geq 0\) से बनने वाले क्षेत्र के शीर्ष कौन से हैं?

What are the vertices of the region formed by \(x\leq 6\), \(y\leq 4\), \(x+2y\geq 10\), \(x\geq 0\), and \(y\geq 0\)?

Explanation opens after your attempt
Correct Answer

A. ((2,4)), ((6,2)), ((6,4))

Step 1

Concept

Inside the rectangle \(0\leq x\leq 6\), \(0\leq y\leq 4\), the part above (x+2y=10) remains. Hence the vertices are ((2,4)), ((6,2)), and ((6,4)).

Step 2

Why this answer is correct

The correct answer is A. ((2,4)), ((6,2)), ((6,4)). Inside the rectangle \(0\leq x\leq 6\), \(0\leq y\leq 4\), the part above (x+2y=10) remains. Hence the vertices are ((2,4)), ((6,2)), and ((6,4)).

Step 3

Exam Tip

आयत \(0\leq x\leq 6\), \(0\leq y\leq 4\) में रेखा (x+2y=10) के ऊपर का भाग बचता है। इसलिए शीर्ष ((2,4)), ((6,2)), ((6,4)) हैं।

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असमानताओं \(x\leq 4\), \(y\leq 3\), \(x+y\geq 5\), \(x\geq 0\), \(y\geq 0\) का हल-क्षेत्र कौन सा है?

Which is the solution region of \(x\leq 4\), \(y\leq 3\), \(x+y\geq 5\), \(x\geq 0\), \(y\geq 0\)?

Explanation opens after your attempt
Correct Answer

B. त्रिभुज जिसके शीर्ष ((2,3)), ((4,1)), ((4,3)) हैंTriangle with vertices ((2,3)), ((4,1)), ((4,3))

Step 1

Concept

From the rectangle \(0\leq x\leq 4\), \(0\leq y\leq 3\), the part above (x+y=5) remains. Its vertices are ((2,3)), ((4,1)), and ((4,3)).

Step 2

Why this answer is correct

The correct answer is B. त्रिभुज जिसके शीर्ष ((2,3)), ((4,1)), ((4,3)) हैं / Triangle with vertices ((2,3)), ((4,1)), ((4,3)). From the rectangle \(0\leq x\leq 4\), \(0\leq y\leq 3\), the part above (x+y=5) remains. Its vertices are ((2,3)), ((4,1)), and ((4,3)).

Step 3

Exam Tip

आयत \(0\leq x\leq 4\), \(0\leq y\leq 3\) से रेखा (x+y=5) के ऊपर का छोटा भाग बचता है। उसके शीर्ष ((2,3)), ((4,1)), ((4,3)) हैं।

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