(5!) का मान क्या है?
What is the value of (5!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (100)
B (120)
C (60)
D (25)
Explanation opens after your attempt
Step 1
Concept
\(5!=5\times4\times3\times2\times1=120\). In factorial notation, multiply the number down to (1).
Step 2
Why this answer is correct
The correct answer is B. (120). \(5!=5\times4\times3\times2\times1=120\). In factorial notation, multiply the number down to (1).
Step 3
Exam Tip
\(5!=5\times4\times3\times2\times1=120\)। फैक्टोरियल में संख्या से (1) तक गुणा करते हैं।
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(0!) का मान कितना माना जाता है?
What is the value of (0!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (0)
B परिभाषित नहीं / Not defined
C (1)
D (10)
Explanation opens after your attempt
Step 1
Concept
In mathematics, (0!) is defined as (1). It is very useful in permutation and combination formulas.
Step 2
Why this answer is correct
The correct answer is C. (1). In mathematics, (0!) is defined as (1). It is very useful in permutation and combination formulas.
Step 3
Exam Tip
गणित में (0!=1) परिभाषित किया जाता है। यह संयोजन और क्रमचय सूत्रों में बहुत उपयोगी है।
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(1!+3!) का मान क्या होगा?
What is the value of (1!+3!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (7)
B (6)
C (4)
D (9)
Explanation opens after your attempt
Step 1
Concept
(1!=1) and (3!=6), so the sum is (7). Find small factorials separately first.
Step 2
Why this answer is correct
The correct answer is A. (7). (1!=1) and (3!=6), so the sum is (7). Find small factorials separately first.
Step 3
Exam Tip
(1!=1) और (3!=6), इसलिए योग (7) है। छोटे फैक्टोरियल पहले अलग-अलग निकालें।
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\(\frac{6!}{4!}\) का सरल मान क्या है?
What is the simplified value of \(\frac{6!}{4!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (24)
B (120)
C (30)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(\frac{6!}{4!}=6\times5=30\). Cancelling the common factorial part is the fastest method.
Step 2
Why this answer is correct
The correct answer is C. (30). \(\frac{6!}{4!}=6\times5=30\). Cancelling the common factorial part is the fastest method.
Step 3
Exam Tip
\(\frac{6!}{4!}=6\times5=30\)। समान फैक्टोरियल भाग को काटना सबसे तेज तरीका है।
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\(\frac{7!}{5!,2!}\) का मान क्या है?
What is the value of \(\frac{7!}{5!,2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (14)
B (21)
C (35)
D (42)
Explanation opens after your attempt
Step 1
Concept
\(\frac{7!}{5!,2!}=\frac{7\times6}{2}=21\). Break the larger factorial down to the smaller factorial first.
Step 2
Why this answer is correct
The correct answer is B. (21). \(\frac{7!}{5!,2!}=\frac{7\times6}{2}=21\). Break the larger factorial down to the smaller factorial first.
Step 3
Exam Tip
\(\frac{7!}{5!,2!}=\frac{7\times6}{2}=21\)। पहले बड़े फैक्टोरियल को छोटे फैक्टोरियल तक तोड़ें।
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(n!) को किस रूप में लिखा जा सकता है?
Which form can represent (n!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (n+(n-1)!)
B (n(n-1)!)
C (n-(n-1)!)
D (\frac{n}{(n-1)!})
Explanation opens after your attempt
Correct Answer
B. (n(n-1)!)
Step 1
Concept
(n!=n(n-1)!) is the correct identity. This formula is used often in factorial questions.
Step 2
Why this answer is correct
The correct answer is B. (n(n-1)!). (n!=n(n-1)!) is the correct identity. This formula is used often in factorial questions.
Step 3
Exam Tip
(n!=n(n-1)!) सही पहचान है। फैक्टोरियल के सवालों में यह सूत्र बार-बार काम आता है।
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(4!+2!) का मान क्या है?
What is the value of (4!+2!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (26)
B (28)
C (24)
D (22)
Explanation opens after your attempt
Step 1
Concept
(4!=24) and (2!=2), so the total is (26). Find each factorial value before adding.
Step 2
Why this answer is correct
The correct answer is A. (26). (4!=24) and (2!=2), so the total is (26). Find each factorial value before adding.
Step 3
Exam Tip
(4!=24) और (2!=2), इसलिए कुल (26) है। जोड़ने से पहले हर फैक्टोरियल का मान निकालें।
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\(\frac{8!}{7!}\) का मान क्या है?
What is the value of \(\frac{8!}{7!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (7)
B (15)
C (56)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(\frac{8!}{7!}=8\) because \(8!=8\times7!\). Keep the factorial expansion short in such questions.
Step 2
Why this answer is correct
The correct answer is D. (8). \(\frac{8!}{7!}=8\) because \(8!=8\times7!\). Keep the factorial expansion short in such questions.
Step 3
Exam Tip
\(\frac{8!}{7!}=8\) क्योंकि \(8!=8\times7!\)। ऐसे प्रश्नों में फैक्टोरियल विस्तार छोटा रखें।
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\(9\times8\times7\) को फैक्टोरियल रूप में कैसे लिखा जा सकता है?
How can \(9\times8\times7\) be written in factorial form?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A \(\frac{9!}{6!}\)
B \(\frac{9!}{7!}\)
C \(\frac{8!}{6!}\)
D \(\frac{7!}{9!}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{9!}{6!}\)
Step 1
Concept
\(9!=9\times8\times7\times6!\), so \(\frac{9!}{6!}=9\times8\times7\). Divide by the factorial after the last required factor.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{9!}{6!}\). \(9!=9\times8\times7\times6!\), so \(\frac{9!}{6!}=9\times8\times7\). Divide by the factorial after the last required factor.
Step 3
Exam Tip
\(9!=9\times8\times7\times6!\), इसलिए \(\frac{9!}{6!}=9\times8\times7\)। अंतिम शेष संख्या के बाद वाले फैक्टोरियल से भाग दें।
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यदि (n!=24), तो (n) का मान क्या है?
If (n!=24), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(4!=4\times3\times2\times1=24\), so (n=4). Remembering small factorial values is useful.
Step 2
Why this answer is correct
The correct answer is B. (4). \(4!=4\times3\times2\times1=24\), so (n=4). Remembering small factorial values is useful.
Step 3
Exam Tip
\(4!=4\times3\times2\times1=24\), इसलिए (n=4)। छोटे फैक्टोरियल के मान याद रखना उपयोगी है।
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\(\frac{5!}{3!}\) का मान क्या होगा?
What will be the value of \(\frac{5!}{3!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (10)
B (15)
C (20)
D (30)
Explanation opens after your attempt
Step 1
Concept
\(\frac{5!}{3!}=5\times4=20\). Write the larger factorial up to the smaller factorial and cancel.
Step 2
Why this answer is correct
The correct answer is C. (20). \(\frac{5!}{3!}=5\times4=20\). Write the larger factorial up to the smaller factorial and cancel.
Step 3
Exam Tip
\(\frac{5!}{3!}=5\times4=20\)। बड़े फैक्टोरियल को छोटे फैक्टोरियल तक लिखकर काटें।
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\(3!\times2!\) का मान क्या है?
What is the value of \(3!\times2!\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (12)
B (10)
C (8)
D (6)
Explanation opens after your attempt
Step 1
Concept
(3!=6) and (2!=2), so the product is (12). Convert factorials into ordinary multiplication to solve.
Step 2
Why this answer is correct
The correct answer is A. (12). (3!=6) and (2!=2), so the product is (12). Convert factorials into ordinary multiplication to solve.
Step 3
Exam Tip
(3!=6) और (2!=2), इसलिए गुणनफल (12) है। फैक्टोरियल को सामान्य गुणा में बदलकर हल करें।
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\(\frac{4!}{2!}\) का सरल मान क्या है?
What is the simplified value of \(\frac{4!}{2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (8)
B (10)
C (12)
D (16)
Explanation opens after your attempt
Step 1
Concept
\(\frac{4!}{2!}=\frac{24}{2}=12\). Cancelling the factorial part also gives the same answer.
Step 2
Why this answer is correct
The correct answer is C. (12). \(\frac{4!}{2!}=\frac{24}{2}=12\). Cancelling the factorial part also gives the same answer.
Step 3
Exam Tip
\(\frac{4!}{2!}=\frac{24}{2}=12\)। फैक्टोरियल भाग को काटकर भी यही उत्तर मिलता है।
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\(\frac{6!}{3!,3!}\) का मान क्या है?
What is the value of \(\frac{6!}{3!,3!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (10)
B (15)
C (18)
D (20)
Explanation opens after your attempt
Step 1
Concept
\(\frac{6!}{3!,3!}=\frac{720}{6\times6}=20\). Keep each factorial value carefully.
Step 2
Why this answer is correct
The correct answer is D. (20). \(\frac{6!}{3!,3!}=\frac{720}{6\times6}=20\). Keep each factorial value carefully.
Step 3
Exam Tip
\(\frac{6!}{3!,3!}=\frac{720}{6\times6}=20\)। हर फैक्टोरियल का मान सावधानी से रखें।
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(5!-4!) का मान क्या है?
What is the value of (5!-4!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (96)
B (72)
C (48)
D (24)
Explanation opens after your attempt
Step 1
Concept
(5!=120) and (4!=24), so the difference is (96). Find both factorials separately before subtracting.
Step 2
Why this answer is correct
The correct answer is A. (96). (5!=120) and (4!=24), so the difference is (96). Find both factorials separately before subtracting.
Step 3
Exam Tip
(5!=120) और (4!=24), इसलिए अंतर (96) है। घटाने से पहले दोनों फैक्टोरियल अलग निकालें।
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(0!+1!+2!) का मान क्या है?
What is the value of (0!+1!+2!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
(0!=1), (1!=1), and (2!=2), so the sum is (4). Do not forget to take (0!) as (1).
Step 2
Why this answer is correct
The correct answer is B. (4). (0!=1), (1!=1), and (2!=2), so the sum is (4). Do not forget to take (0!) as (1).
Step 3
Exam Tip
(0!=1), (1!=1) और (2!=2), इसलिए योग (4) है। (0!) को (1) लेना न भूलें।
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\(\frac{10!}{8!}\) का मान क्या है?
What is the value of \(\frac{10!}{8!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (80)
B (90)
C (100)
D (720)
Explanation opens after your attempt
Step 1
Concept
\(\frac{10!}{8!}=10\times9=90\). Cancelling factorials makes the calculation shorter.
Step 2
Why this answer is correct
The correct answer is B. (90). \(\frac{10!}{8!}=10\times9=90\). Cancelling factorials makes the calculation shorter.
Step 3
Exam Tip
\(\frac{10!}{8!}=10\times9=90\)। फैक्टोरियल काटने से गणना छोटी हो जाती है।
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(4!) का सही विस्तार कौन सा है?
Which is the correct expansion of (4!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (4+3+2+1)
B \(4\times4\times4\times4\)
C \(4\times3\times2\times1\)
D \(4\times3+2\times1\)
Explanation opens after your attempt
Correct Answer
C. \(4\times3\times2\times1\)
Step 1
Concept
(4!) means \(4\times3\times2\times1\). Factorial uses multiplication, not addition.
Step 2
Why this answer is correct
The correct answer is C. \(4\times3\times2\times1\). (4!) means \(4\times3\times2\times1\). Factorial uses multiplication, not addition.
Step 3
Exam Tip
(4!) का अर्थ \(4\times3\times2\times1\) है। फैक्टोरियल में जोड़ नहीं, गुणा होता है।
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\(1\times2\times3\times4\times5\times6\) को किस रूप में लिखेंगे?
How will you write \(1\times2\times3\times4\times5\times6\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (5!)
B (6!)
C (7!)
D \(6^2\)
Explanation opens after your attempt
Step 1
Concept
The product from (1) to (6) is (6!). In factorial multiplication, writing in reverse or forward order gives the same value.
Step 2
Why this answer is correct
The correct answer is B. (6!). The product from (1) to (6) is (6!). In factorial multiplication, writing in reverse or forward order gives the same value.
Step 3
Exam Tip
(1) से (6) तक का गुणनफल (6!) होता है। फैक्टोरियल में क्रम उल्टा या सीधा लिखने से मान नहीं बदलता।
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\(\frac{9!}{9!}\) का मान क्या है?
What is the value of \(\frac{9!}{9!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (0)
B (9)
C (1)
D (81)
Explanation opens after your attempt
Step 1
Concept
Any non-zero quantity divided by itself is (1). Therefore, \(\frac{9!}{9!}=1\).
Step 2
Why this answer is correct
The correct answer is C. (1). Any non-zero quantity divided by itself is (1). Therefore, \(\frac{9!}{9!}=1\).
Step 3
Exam Tip
किसी भी अशून्य समान संख्या का अपने आप से भाग (1) होता है। इसलिए \(\frac{9!}{9!}=1\) है।
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(\frac{(n+1)!}{n!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+1)!}{n!})?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (n)
B (n+1)
C (n!)
D (1)
Explanation opens after your attempt
Step 1
Concept
((n+1)!=(n+1)n!), so division leaves (n+1). Remember the factorial identity.
Step 2
Why this answer is correct
The correct answer is B. (n+1). ((n+1)!=(n+1)n!), so division leaves (n+1). Remember the factorial identity.
Step 3
Exam Tip
((n+1)!=(n+1)n!), इसलिए भाग देने पर (n+1) बचता है। फैक्टोरियल पहचान को याद रखें।
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\(\frac{7!}{6!,1!}\) का मान क्या है?
What is the value of \(\frac{7!}{6!,1!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (6)
B (7)
C (14)
D (1)
Explanation opens after your attempt
Step 1
Concept
\(\frac{7!}{6!,1!}=\frac{7\times6!}{6!\times1}=7\). The value of (1!) is (1).
Step 2
Why this answer is correct
The correct answer is B. (7). \(\frac{7!}{6!,1!}=\frac{7\times6!}{6!\times1}=7\). The value of (1!) is (1).
Step 3
Exam Tip
\(\frac{7!}{6!,1!}=\frac{7\times6!}{6!\times1}=7\)। (1!) का मान (1) होता है।
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(3!+4!) का मान क्या है?
What is the value of (3!+4!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (24)
B (30)
C (36)
D (42)
Explanation opens after your attempt
Step 1
Concept
(3!=6) and (4!=24), so the sum is (30). Find factorial values before adding them.
Step 2
Why this answer is correct
The correct answer is B. (30). (3!=6) and (4!=24), so the sum is (30). Find factorial values before adding them.
Step 3
Exam Tip
(3!=6) और (4!=24), इसलिए योग (30) है। फैक्टोरियल को जोड़ने से पहले उसका मान निकालें।
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(6!-5!) का मान क्या होगा?
What will be the value of (6!-5!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (600)
B (500)
C (720)
D (120)
Explanation opens after your attempt
Step 1
Concept
(6!=720) and (5!=120), so the difference is (600). Write the value of the larger factorial carefully.
Step 2
Why this answer is correct
The correct answer is A. (600). (6!=720) and (5!=120), so the difference is (600). Write the value of the larger factorial carefully.
Step 3
Exam Tip
(6!=720) और (5!=120), इसलिए अंतर (600) है। बड़े फैक्टोरियल का मान ध्यान से लिखें।
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\(2!\times4!\) का मान क्या है?
What is the value of \(2!\times4!\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (36)
B (42)
C (48)
D (56)
Explanation opens after your attempt
Step 1
Concept
(2!=2) and (4!=24), so the product is (48). First find factorial values and then multiply.
Step 2
Why this answer is correct
The correct answer is C. (48). (2!=2) and (4!=24), so the product is (48). First find factorial values and then multiply.
Step 3
Exam Tip
(2!=2) और (4!=24), इसलिए गुणनफल (48) है। पहले फैक्टोरियल मान निकालकर फिर गुणा करें।
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\(\frac{8!}{5!}\) का मान क्या है?
What is the value of \(\frac{8!}{5!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (336)
B (120)
C (56)
D (720)
Explanation opens after your attempt
Step 1
Concept
\(\frac{8!}{5!}=8\times7\times6=336\). Expand down to the smaller factorial and cancel.
Step 2
Why this answer is correct
The correct answer is A. (336). \(\frac{8!}{5!}=8\times7\times6=336\). Expand down to the smaller factorial and cancel.
Step 3
Exam Tip
\(\frac{8!}{5!}=8\times7\times6=336\)। छोटे फैक्टोरियल तक विस्तार करके काटें।
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यदि (n=3), तो ((n+2)!) का मान क्या है?
If (n=3), what is the value of ((n+2)!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (24)
B (120)
C (720)
D (6)
Explanation opens after your attempt
Step 1
Concept
(n+2=5), so ((n+2)!=5!=120). First find the value inside the brackets.
Step 2
Why this answer is correct
The correct answer is B. (120). (n+2=5), so ((n+2)!=5!=120). First find the value inside the brackets.
Step 3
Exam Tip
(n+2=5), इसलिए ((n+2)!=5!=120)। पहले कोष्ठक का मान निकालें।
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(\frac{(n+2)!}{n!}) का सरल रूप क्या है?
What is the simplified form of (\frac{(n+2)!}{n!})?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (n+2)
B (n(n+1))
C ((n+2)(n+1))
D (2n)
Explanation opens after your attempt
Correct Answer
C. ((n+2)(n+1))
Step 1
Concept
((n+2)!=(n+2)(n+1)n!), so (n!) cancels. The remaining part is ((n+2)(n+1)).
Step 2
Why this answer is correct
The correct answer is C. ((n+2)(n+1)). ((n+2)!=(n+2)(n+1)n!), so (n!) cancels. The remaining part is ((n+2)(n+1)).
Step 3
Exam Tip
((n+2)!=(n+2)(n+1)n!), इसलिए (n!) कट जाएगा। शेष ((n+2)(n+1)) है।
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(5!) और (4!) में कौन सा बड़ा है?
Which is greater between (5!) and (4!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (4!)
B दोनों बराबर / Both are equal
C (5!)
D तुलना नहीं हो सकती / Cannot be compared
Explanation opens after your attempt
Step 1
Concept
(5!=120) and (4!=24), so (5!) is greater. The factorial of a larger positive integer is generally larger.
Step 2
Why this answer is correct
The correct answer is C. (5!). (5!=120) and (4!=24), so (5!) is greater. The factorial of a larger positive integer is generally larger.
Step 3
Exam Tip
(5!=120) और (4!=24), इसलिए (5!) बड़ा है। बड़े धनात्मक पूर्णांक का फैक्टोरियल सामान्यतः बड़ा होता है।
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\(\frac{4!+3!}{3!}\) का मान क्या है?
What is the value of \(\frac{4!+3!}{3!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
\(\frac{4!+3!}{3!}=\frac{24+6}{6}=5\). Simplify the numerator with addition first.
Step 2
Why this answer is correct
The correct answer is B. (5). \(\frac{4!+3!}{3!}=\frac{24+6}{6}=5\). Simplify the numerator with addition first.
Step 3
Exam Tip
\(\frac{4!+3!}{3!}=\frac{24+6}{6}=5\)। जोड़ वाले अंश को पहले सरल करें।
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(7!) में (7) के बाद अगला गुणक कौन सा आता है?
In (7!), which factor comes immediately after (7)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (8)
B (7)
C (6)
D (1)
Explanation opens after your attempt
Step 1
Concept
\(7!=7\times6\times5\times4\times3\times2\times1\). In factorial notation, the numbers decrease step by step.
Step 2
Why this answer is correct
The correct answer is C. (6). \(7!=7\times6\times5\times4\times3\times2\times1\). In factorial notation, the numbers decrease step by step.
Step 3
Exam Tip
\(7!=7\times6\times5\times4\times3\times2\times1\)। फैक्टोरियल में संख्या घटती जाती है।
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\(3!\times0!\) का मान क्या है?
What is the value of \(3!\times0!\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (0)
B (3)
C (6)
D (9)
Explanation opens after your attempt
Step 1
Concept
(3!=6) and (0!=1), so the product is (6). Treating (0!) as (0) is a common mistake.
Step 2
Why this answer is correct
The correct answer is C. (6). (3!=6) and (0!=1), so the product is (6). Treating (0!) as (0) is a common mistake.
Step 3
Exam Tip
(3!=6) और (0!=1), इसलिए गुणनफल (6) है। (0!) को (0) समझना सामान्य गलती है।
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\(\frac{6!}{2!,4!}\) का मान क्या है?
What is the value of \(\frac{6!}{2!,4!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (10)
B (12)
C (15)
D (20)
Explanation opens after your attempt
Step 1
Concept
\(\frac{6!}{2!,4!}=\frac{6\times5}{2}=15\). Cancel the smaller factorial from the larger factorial.
Step 2
Why this answer is correct
The correct answer is C. (15). \(\frac{6!}{2!,4!}=\frac{6\times5}{2}=15\). Cancel the smaller factorial from the larger factorial.
Step 3
Exam Tip
\(\frac{6!}{2!,4!}=\frac{6\times5}{2}=15\)। बड़े फैक्टोरियल से छोटे फैक्टोरियल को काटें।
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(2!+2!+2!) का मान क्या है?
What is the value of (2!+2!+2!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (4)
B (6)
C (8)
D (12)
Explanation opens after your attempt
Step 1
Concept
(2!=2), so (2+2+2=6). Find the repeated factorial once first.
Step 2
Why this answer is correct
The correct answer is B. (6). (2!=2), so (2+2+2=6). Find the repeated factorial once first.
Step 3
Exam Tip
(2!=2), इसलिए (2+2+2=6)। दोहराए गए फैक्टोरियल को पहले एक बार निकालें।
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\(6\times5\times4!\) किसके बराबर है?
\(6\times5\times4!\) is equal to which of the following?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (5!)
B (6!)
C (7!)
D (4!)
Explanation opens after your attempt
Step 1
Concept
\(6!=6\times5\times4!\), so the given product is (6!). A factorial can be identified from the middle expansion too.
Step 2
Why this answer is correct
The correct answer is B. (6!). \(6!=6\times5\times4!\), so the given product is (6!). A factorial can be identified from the middle expansion too.
Step 3
Exam Tip
\(6!=6\times5\times4!\), इसलिए दिया गया गुणनफल (6!) है। फैक्टोरियल को बीच से भी पहचाना जा सकता है।
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\(\frac{5!}{5}\) का मान क्या है?
What is the value of \(\frac{5!}{5}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (12)
B (20)
C (24)
D (30)
Explanation opens after your attempt
Step 1
Concept
\(5!=5\times4!\), so \(\frac{5!}{5}=4!=24\). Cancel common factors in factorial expressions.
Step 2
Why this answer is correct
The correct answer is C. (24). \(5!=5\times4!\), so \(\frac{5!}{5}=4!=24\). Cancel common factors in factorial expressions.
Step 3
Exam Tip
\(5!=5\times4!\), इसलिए \(\frac{5!}{5}=4!=24\)। फैक्टोरियल में सामान्य गुणक काटें।
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(4!-3!) का मान क्या है?
What is the value of (4!-3!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (18)
B (12)
C (10)
D (6)
Explanation opens after your attempt
Step 1
Concept
(4!=24) and (3!=6), so the difference is (18). Do not treat the factorial sign as ordinary subtraction.
Step 2
Why this answer is correct
The correct answer is A. (18). (4!=24) and (3!=6), so the difference is (18). Do not treat the factorial sign as ordinary subtraction.
Step 3
Exam Tip
(4!=24) और (3!=6), इसलिए अंतर (18) है। फैक्टोरियल चिन्ह को साधारण घटाव न समझें।
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यदि (x=4!), तो (x) का मान क्या है?
If (x=4!), what is the value of (x)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (16)
B (20)
C (24)
D (28)
Explanation opens after your attempt
Step 1
Concept
\(4!=4\times3\times2\times1=24\), so (x=24). In variable-based questions, first evaluate the factorial.
Step 2
Why this answer is correct
The correct answer is C. (24). \(4!=4\times3\times2\times1=24\), so (x=24). In variable-based questions, first evaluate the factorial.
Step 3
Exam Tip
\(4!=4\times3\times2\times1=24\), इसलिए (x=24)। चर वाले सवाल में पहले फैक्टोरियल का मान निकालें।
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\(\frac{3!}{2!}\) का मान क्या है?
What is the value of \(\frac{3!}{2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (2)
B (3)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(\frac{3!}{2!}=\frac{3\times2!}{2!}=3\). Cancel the common (2!).
Step 2
Why this answer is correct
The correct answer is B. (3). \(\frac{3!}{2!}=\frac{3\times2!}{2!}=3\). Cancel the common (2!).
Step 3
Exam Tip
\(\frac{3!}{2!}=\frac{3\times2!}{2!}=3\)। समान (2!) को काट दें।
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\(5\times4\times3!\) किसके बराबर है?
\(5\times4\times3!\) is equal to which of the following?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (3!)
B (4!)
C (5!)
D (6!)
Explanation opens after your attempt
Step 1
Concept
\(5!=5\times4\times3!\), so the given form is (5!). Recognizing factorial expansion is important.
Step 2
Why this answer is correct
The correct answer is C. (5!). \(5!=5\times4\times3!\), so the given form is (5!). Recognizing factorial expansion is important.
Step 3
Exam Tip
\(5!=5\times4\times3!\), इसलिए दिया गया रूप (5!) है। फैक्टोरियल विस्तार को पहचानना जरूरी है।
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(6!) का मान क्या है?
What is the value of (6!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (120)
B (360)
C (720)
D (840)
Explanation opens after your attempt
Step 1
Concept
\(6!=6\times5\times4\times3\times2\times1=720\). If you remember (5!=120), then use \(6!=6\times120\).
Step 2
Why this answer is correct
The correct answer is C. (720). \(6!=6\times5\times4\times3\times2\times1=720\). If you remember (5!=120), then use \(6!=6\times120\).
Step 3
Exam Tip
\(6!=6\times5\times4\times3\times2\times1=720\)। (5!=120) याद हो तो \(6!=6\times120\) करें।
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\(\frac{7!}{7}\) का मान क्या है?
What is the value of \(\frac{7!}{7}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (5!)
B (6!)
C (7!)
D (8!)
Explanation opens after your attempt
Step 1
Concept
\(7!=7\times6!\), so \(\frac{7!}{7}=6!\). Break the factorial into factors and cancel.
Step 2
Why this answer is correct
The correct answer is B. (6!). \(7!=7\times6!\), so \(\frac{7!}{7}=6!\). Break the factorial into factors and cancel.
Step 3
Exam Tip
\(7!=7\times6!\), इसलिए \(\frac{7!}{7}=6!\)। फैक्टोरियल को गुणनखंड में तोड़कर काटें।
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\(\frac{4!}{0!}\) का मान क्या है?
What is the value of \(\frac{4!}{0!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (0)
B (1)
C (12)
D (24)
Explanation opens after your attempt
Step 1
Concept
(4!=24) and (0!=1), so the quotient is (24). Always take (0!) as (1).
Step 2
Why this answer is correct
The correct answer is D. (24). (4!=24) and (0!=1), so the quotient is (24). Always take (0!) as (1).
Step 3
Exam Tip
(4!=24) और (0!=1), इसलिए भागफल (24) है। (0!) हमेशा (1) रखें।
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यदि (n!=120), तो (n) का मान क्या है?
If (n!=120), what is the value of (n)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(5!=120), so (n=5). Small factorial values help answer quickly in exams.
Step 2
Why this answer is correct
The correct answer is B. (5). (5!=120), so (n=5). Small factorial values help answer quickly in exams.
Step 3
Exam Tip
(5!=120), इसलिए (n=5)। छोटे फैक्टोरियल मान परीक्षा में जल्दी उत्तर दिलाते हैं।
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((3+1)!) का मान क्या है?
What is the value of ((3+1)!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (4)
B (12)
C (24)
D (36)
Explanation opens after your attempt
Step 1
Concept
First calculate (3+1=4), then (4!=24). The expression inside the brackets is evaluated first.
Step 2
Why this answer is correct
The correct answer is C. (24). First calculate (3+1=4), then (4!=24). The expression inside the brackets is evaluated first.
Step 3
Exam Tip
पहले (3+1=4) करें, फिर (4!=24)। कोष्ठक के अंदर की गणना पहले होती है।
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(3!+0!) का मान क्या है?
What is the value of (3!+0!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
(3!=6) and (0!=1), so the sum is (7). Pay special attention in questions involving (0!).
Step 2
Why this answer is correct
The correct answer is B. (7). (3!=6) and (0!=1), so the sum is (7). Pay special attention in questions involving (0!).
Step 3
Exam Tip
(3!=6) और (0!=1), इसलिए योग (7) है। (0!) वाले सवाल में विशेष ध्यान रखें।
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(8!) को (7!) की सहायता से कैसे लिखेंगे?
How can (8!) be written using (7!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (8+7!)
B \(8\times7!\)
C \(7\times8!\)
D \(\frac{7!}{8}\)
Explanation opens after your attempt
Correct Answer
B. \(8\times7!\)
Step 1
Concept
\(8!=8\times7!\). This is a basic factorial identity.
Step 2
Why this answer is correct
The correct answer is B. \(8\times7!\). \(8!=8\times7!\). This is a basic factorial identity.
Step 3
Exam Tip
\(8!=8\times7!\) होता है। यह फैक्टोरियल की मूल पहचान है।
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\(\frac{5!}{4!}+1\) का मान क्या है?
What is the value of \(\frac{5!}{4!}+1\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (5)
B (6)
C (7)
D (9)
Explanation opens after your attempt
Step 1
Concept
\(\frac{5!}{4!}=5\), so (5+1=6). Simplify the quotient first and then add.
Step 2
Why this answer is correct
The correct answer is B. (6). \(\frac{5!}{4!}=5\), so (5+1=6). Simplify the quotient first and then add.
Step 3
Exam Tip
\(\frac{5!}{4!}=5\), इसलिए (5+1=6)। पहले भाग को सरल करके फिर जोड़ें।
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\(\frac{2!+3!}{2!}\) का मान क्या है?
What is the value of \(\frac{2!+3!}{2!}\)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
\(\frac{2!+3!}{2!}=\frac{2+6}{2}=4\). Complete the addition in the numerator first.
Step 2
Why this answer is correct
The correct answer is C. (4). \(\frac{2!+3!}{2!}=\frac{2+6}{2}=4\). Complete the addition in the numerator first.
Step 3
Exam Tip
\(\frac{2!+3!}{2!}=\frac{2+6}{2}=4\)। अंश में जोड़ पहले पूरा करें।
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(7!) में कुल कितने गुणक लिखे जाते हैं?
How many factors are written in (7!)?
#factorial_notation
#permutations_combinations
#class_11
#easy
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A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(7!=7\times6\times5\times4\times3\times2\times1\), which has (7) factors. In (n!), factors run from (n) down to (1).
Step 2
Why this answer is correct
The correct answer is C. (7). \(7!=7\times6\times5\times4\times3\times2\times1\), which has (7) factors. In (n!), factors run from (n) down to (1).
Step 3
Exam Tip
\(7!=7\times6\times5\times4\times3\times2\times1\), इसमें (7) गुणक हैं। (n!) में (n) से (1) तक के गुणक आते हैं।
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