असमानता \(3\leq \frac{x+2}{5}\leq 6\) का हल क्या है?

What is the solution of \(3\leq \frac{x+2}{5}\leq 6\)?

Explanation opens after your attempt
Correct Answer

A. \(13\leq x\leq 28\)

Step 1

Concept

Multiplying by (5) gives \(15\leq x+2\leq 30\). Subtracting (2) gives \(13\leq x\leq 28\).

Step 2

Why this answer is correct

The correct answer is A. \(13\leq x\leq 28\). Multiplying by (5) gives \(15\leq x+2\leq 30\). Subtracting (2) gives \(13\leq x\leq 28\).

Step 3

Exam Tip

(5) से गुणा करने पर \(15\leq x+2\leq 30\) मिलता है। फिर (2) घटाने पर \(13\leq x\leq 28\) मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(3\leq \frac{x+2}{5}\leq 6\) का हल क्या है? / What is the solution of \(3\leq \frac{x+2}{5}\leq 6\)?

Correct Answer: A. \(13\leq x\leq 28\). Explanation: (5) से गुणा करने पर \(15\leq x+2\leq 30\) मिलता है। फिर (2) घटाने पर \(13\leq x\leq 28\) मिलता है। / Multiplying by (5) gives \(15\leq x+2\leq 30\). Subtracting (2) gives \(13\leq x\leq 28\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by (5) gives \(15\leq x+2\leq 30\). Subtracting (2) gives \(13\leq x\leq 28\).

What exam hint can help solve this Mathematics question?

(5) से गुणा करने पर \(15\leq x+2\leq 30\) मिलता है। फिर (2) घटाने पर \(13\leq x\leq 28\) मिलता है।