\(यदि (U={1,2,3,\ldots,18}), (A={x:x\) 2 से विभाज्य है\(}) और (B={x:x\) 3 से विभाज्य है\(}) है, तो (A^c\cap B^c) में कितने तत्व होंगे\)?
\(If (U={1,2,3,\ldots,18}), (A={x:x\) is divisible by \(2}), and (B={x:x\) is divisible by \(3}), how many elements are in (A^c\cap B^c)\)?
Explanation opens after your attempt
A. (6)
Concept
\(A^c\cap B^c\) contains numbers divisible by neither (2) nor (3). These numbers are (1,5,7,11,13,17).
Why this answer is correct
The correct answer is A. (6). \(A^c\cap B^c\) contains numbers divisible by neither (2) nor (3). These numbers are (1,5,7,11,13,17).
Exam Tip
\(A^c\cap B^c\) में वे संख्याएं हैं जो न (2) से और न (3) से विभाज्य हैं। ऐसी संख्याएं (1,5,7,11,13,17) हैं।
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