वास्तविक मानों वाले फलन (f(x)=\sqrt{9-x-2}) के लिए सही प्रांत और परिसर कौन सा है?
For the real valued function (f(x)=\sqrt{9-x-2}), which option gives the correct domain and range?
Explanation opens after your attempt
A. प्रांत ( [-3,3] ), परिसर ( [0,3] )Domain ( [-3,3] ), range ( [0,3] )
Concept
For \(\sqrt{9-x^2}\) to be real, \(9-x^2\ge 0\), so \(x\in[-3,3]\) and \(f(x)\in[0,3]\). In exams, always keep the expression inside a square root \(\ge 0\).
Why this answer is correct
The correct answer is A. प्रांत ( [-3,3] ), परिसर ( [0,3] ) / Domain ( [-3,3] ), range ( [0,3] ). For \(\sqrt{9-x^2}\) to be real, \(9-x^2\ge 0\), so \(x\in[-3,3]\) and \(f(x)\in[0,3]\). In exams, always keep the expression inside a square root \(\ge 0\).
Exam Tip
\(\sqrt{9-x^2}\) वास्तविक होने के लिए \(9-x^2\ge 0\), इसलिए \(x\in[-3,3]\) और \(f(x)\in[0,3]\)। परीक्षा में वर्गमूल वाले फलन में अंदर की राशि को हमेशा \(\ge 0\) रखें।
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