Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 111-120 of 609 questions.
How many ways are there to choose (6) files from (9) different files?
D. (84)
\(\binom{9}{6}=\binom{9}{3}=84\) है। पूरक चयन से गणना आसान होती है। / \(\binom{9}{6}=\binom{9}{3}=84\). Complementary selection makes calculation easier.
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From (6) boys and (5) girls, in how many ways can (3) boys and (1) girl be selected?
A. (100)
तरीके \(\binom{6}{3}\binom{5}{1}=20\cdot5=100\) हैं। अलग वर्गों से चयन में गुणा करें। / The ways are \(\binom{6}{3}\binom{5}{1}=20\cdot5=100\). Multiply selections from different groups.
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From (8) red and (7) white flowers, in how many ways can (2) red and (2) white flowers be selected?
B. (588)
चयन \(\binom{8}{2}\binom{7}{2}=28\cdot21=588\) है। हर रंग के लिए अलग संयोजन लगाएं। / The selection is \(\binom{8}{2}\binom{7}{2}=28\cdot21=588\). Use a separate combination for each color.
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In how many ways can a team of (2) doctors and (1) nurse be formed from (7) doctors and (4) nurses?
C. (84)
तरीके \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\) हैं। शर्तों को अलग-अलग गिनें। / The ways are \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\). Count each condition separately.
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D. (200)
तरीके \(\binom{5}{2}\binom{6}{3}=10\cdot20=200\) हैं। अलग विषयों के चयन को गुणा करें। / The ways are \(\binom{5}{2}\binom{6}{3}=10\cdot20=200\). Multiply selections from different subjects.
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What is the maximum number of handshakes among (20) persons?
A. (190)
हर हाथ मिलाना (2) व्यक्तियों की एक जोड़ी है। इसलिए \(\binom{20}{2}=190\) होगा। / Each handshake is a pair of (2) persons. Therefore \(\binom{20}{2}=190\).
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B. (55)
हर मैच (2) टीमों की जोड़ी से बनता है। कुल मैच \(\binom{11}{2}=55\) होंगे। / Each match is formed by a pair of (2) teams. The total matches are \(\binom{11}{2}=55\).
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C. (364)
त्रिभुज के लिए (3) बिंदु चाहिए। इसलिए \(\binom{14}{3}=364\) है। / A triangle needs (3) points. Hence \(\binom{14}{3}=364\).
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How many straight lines can be formed from (12) points if no (3) points lie on the same line?
B. (66)
एक रेखा (2) बिंदुओं से बनती है। इसलिए \(\binom{12}{2}=66\) सही है। / A line is formed by (2) points. Hence \(\binom{12}{2}=66\) is correct.
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There are (10) points, no (3) of which are collinear. How many circles will be determined?
C. (120)
एक वृत्त (3) बिंदुओं से निर्धारित होता है। अतः \(\binom{10}{3}=120\) होगा। / A circle is determined by (3) points. Thus \(\binom{10}{3}=120\).
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