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Which option gives the correct prime factorisation of (756)?
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Answer and explanation
Correct answer: (2^2\times3^3\times7)
Step 1: Write (756) as (4\times189). Step 2: (4=2^2) and (189=27\times7=3^3\times7), so (756=2^2\times3^3\times7). Step 3: Break a large number into convenient factors first.
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What is the correct answer to this question?
(2^2\times3^3\times7)
Why is this the correct answer?
Step 1: Write (756) as (4\times189). Step 2: (4=2^2) and (189=27\times7=3^3\times7), so (756=2^2\times3^3\times7). Step 3: Break a large number into convenient factors first.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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