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Which number is rational even though irrational square roots appear in it?कौन सी संख्या परिमेय है, जबकि उसमें अपरिमेय वर्गमूल दिखाई दे रहे हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((\sqrt{6}+\sqrt{2})(\sqrt{6}-\sqrt{2}))((\sqrt{6}+\sqrt{2})(\sqrt{6}-\sqrt{2}))
Step 1: The first option is a product of conjugate terms. Step 2: ((\sqrt{6}+\sqrt{2})(\sqrt{6}-\sqrt{2})=6-2=4), which is rational. Step 3: Identifying conjugates helps remove radicals quickly.चरण 1: पहला विकल्प संयुग्मी पदों का गुणनफल है। चरण 2: ((\sqrt{6}+\sqrt{2})(\sqrt{6}-\sqrt{2})=6-2=4), जो परिमेय है। चरण 3: संयुग्मी पद पहचानने से वर्गमूल जल्दी हट जाते हैं।
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