\(\frac{4^3\cdot2^{-1}}{8}\) का मान क्या है?
What is the value of \(\frac{4^3\cdot2^{-1}}{8}\)?
Explanation opens after your attempt
B. (4)
Concept
(43=\(2^2\)3=26), \(2^{-1}\), and \(8=2^3\). The total exponent is (6-1-3=2), so the value is \(2^2=4\).
Why this answer is correct
The correct answer is B. (4). (43=\(2^2\)3=26), \(2^{-1}\), and \(8=2^3\). The total exponent is (6-1-3=2), so the value is \(2^2=4\).
Exam Tip
(43=\(2^2\)3=26), \(2^{-1}\) और \(8=2^3\) है। कुल घात (6-1-3=2) है इसलिए मान \(2^2=4\) है।
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