\(\frac{4^3\cdot2^{-1}}{8}\) का मान क्या है?

What is the value of \(\frac{4^3\cdot2^{-1}}{8}\)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

(43=\(2^2\)3=26), \(2^{-1}\), and \(8=2^3\). The total exponent is (6-1-3=2), so the value is \(2^2=4\).

Step 2

Why this answer is correct

The correct answer is B. (4). (43=\(2^2\)3=26), \(2^{-1}\), and \(8=2^3\). The total exponent is (6-1-3=2), so the value is \(2^2=4\).

Step 3

Exam Tip

(43=\(2^2\)3=26), \(2^{-1}\) और \(8=2^3\) है। कुल घात (6-1-3=2) है इसलिए मान \(2^2=4\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{4^3\cdot2^{-1}}{8}\) का मान क्या है? / What is the value of \(\frac{4^3\cdot2^{-1}}{8}\)?

Correct Answer: B. (4). Explanation: (43=\(2^2\)3=26), \(2^{-1}\) और \(8=2^3\) है। कुल घात (6-1-3=2) है इसलिए मान \(2^2=4\) है। / (43=\(2^2\)3=26), \(2^{-1}\), and \(8=2^3\). The total exponent is (6-1-3=2), so the value is \(2^2=4\).

Which concept should I revise for this Mathematics MCQ?

(43=\(2^2\)3=26), \(2^{-1}\), and \(8=2^3\). The total exponent is (6-1-3=2), so the value is \(2^2=4\).

What exam hint can help solve this Mathematics question?

(43=\(2^2\)3=26), \(2^{-1}\) और \(8=2^3\) है। कुल घात (6-1-3=2) है इसलिए मान \(2^2=4\) है।