\(\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{3}-\sqrt{2}}\) का मान क्या है?
What is the value of \(\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{3}-\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{3}\)
Concept
The first term becomes \(\sqrt{3}-\sqrt{2}\), and the second becomes \(\sqrt{3}+\sqrt{2}\), so the sum is \(2\sqrt{3}\). In exams, rationalize both denominators separately.
Why this answer is correct
The correct answer is A. \(2\sqrt{3}\). The first term becomes \(\sqrt{3}-\sqrt{2}\), and the second becomes \(\sqrt{3}+\sqrt{2}\), so the sum is \(2\sqrt{3}\). In exams, rationalize both denominators separately.
Exam Tip
पहला पद \(\sqrt{3}-\sqrt{2}\) और दूसरा पद \(\sqrt{3}+\sqrt{2}\) बनता है, इसलिए योग \(2\sqrt{3}\) है। परीक्षा में दोनों हरों को अलग-अलग परिमेय बनाएं।
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