0 reads0 ratings0 helpful
In the equation \(x^2-4\sqrt{2}x+8=0\), what is the value of \(b\) when it is written in the form \(ax^2+bx+c=0\)?समीकरण \(x^2-4\sqrt{2}x+8=0\) में, \(ax^2+bx+c=0\) के रूप में लिखने पर \(b\) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-4\sqrt{2}\)\(-4\sqrt{2}\)
Compare \(x^2-4\sqrt{2}x+8=0\) with \(ax^2+bx+c=0\). The coefficient of \(x\) is \(-4\sqrt{2}\), so \(b=-4\sqrt{2}\).\(x^2-4\sqrt{2}x+8=0\) की तुलना \(ax^2+bx+c=0\) से करें। \(x\) का गुणांक \(-4\sqrt{2}\) है, इसलिए \(b=-4\sqrt{2}\)।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
