समीकरण \(x^2-4\sqrt{2}x+8=0\) में (b) का मान क्या है?

What is the value of (b) in \(x^2-4\sqrt{2}x+8=0\)?

Explanation opens after your attempt
Correct Answer

A. \(-4\sqrt{2}\)

Step 1

Concept

The coefficient attached to (x) is \(-4\sqrt{2}\). Keep the sign with radical coefficients too.

Step 2

Why this answer is correct

The correct answer is A. \(-4\sqrt{2}\). The coefficient attached to (x) is \(-4\sqrt{2}\). Keep the sign with radical coefficients too.

Step 3

Exam Tip

(x) के साथ लगा गुणांक \(-4\sqrt{2}\) है। करणी वाले गुणांक में भी चिन्ह साथ रखें।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2-4\sqrt{2}x+8=0\) में (b) का मान क्या है? / What is the value of (b) in \(x^2-4\sqrt{2}x+8=0\)?

Correct Answer: A. \(-4\sqrt{2}\). Explanation: (x) के साथ लगा गुणांक \(-4\sqrt{2}\) है। करणी वाले गुणांक में भी चिन्ह साथ रखें। / The coefficient attached to (x) is \(-4\sqrt{2}\). Keep the sign with radical coefficients too.

Which concept should I revise for this Mathematics MCQ?

The coefficient attached to (x) is \(-4\sqrt{2}\). Keep the sign with radical coefficients too.

What exam hint can help solve this Mathematics question?

(x) के साथ लगा गुणांक \(-4\sqrt{2}\) है। करणी वाले गुणांक में भी चिन्ह साथ रखें।