\(\sqrt{200}-\sqrt{72}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{200}-\sqrt{72}\)?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{2}\)

Step 1

Concept

\(\sqrt{200}=10\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\).

Step 2

Why this answer is correct

\(10\sqrt{2}-6\sqrt{2}=4\sqrt{2}\).

Step 3

Exam Tip

Before subtracting radicals, write both terms in simplified form. चरण 1: \(\sqrt{200}=10\sqrt{2}\) और \(\sqrt{72}=6\sqrt{2}\)। चरण 2: \(10\sqrt{2}-6\sqrt{2}=4\sqrt{2}\)। चरण 3: वर्गमूल घटाने में पहले दोनों पदों को सरल रूप में लिखें।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{200}-\sqrt{72}\) का सरल रूप क्या है? / What is the simplified form of \(\sqrt{200}-\sqrt{72}\)?

Correct Answer: A. \(4\sqrt{2}\). Explanation: चरण 1: \(\sqrt{200}=10\sqrt{2}\) और \(\sqrt{72}=6\sqrt{2}\)। चरण 2: \(10\sqrt{2}-6\sqrt{2}=4\sqrt{2}\)। चरण 3: वर्गमूल घटाने में पहले दोनों पदों को सरल रूप में लिखें। / Step 1: \(\sqrt{200}=10\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\). Step 2: \(10\sqrt{2}-6\sqrt{2}=4\sqrt{2}\). Step 3: Before subtracting radicals, write both terms in simplified form.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{200}=10\sqrt{2}\) and \(\sqrt{72}=6\sqrt{2}\).

What exam hint can help solve this Mathematics question?

Before subtracting radicals, write both terms in simplified form. चरण 1: \(\sqrt{200}=10\sqrt{2}\) और \(\sqrt{72}=6\sqrt{2}\)। चरण 2: \(10\sqrt{2}-6\sqrt{2}=4\sqrt{2}\)। चरण 3: वर्गमूल घटाने में पहले दोनों पदों को सरल रूप में लिखें।