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What is the simplified form of \(\left(\frac{4x^{2}y^{-3}}{2x^{-1}y}\right)^{-2}\), where \(x\neq0\) and \(y\neq0\)?\(\left(\frac{4x^{2}y^{-3}}{2x^{-1}y}\right)^{-2}\) का सरल रूप क्या है, जहाँ \(x\neq0\) और \(y\neq0\)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{y^{8}}{4x^{6}}\)\(\frac{y^{8}}{4x^{6}}\)
Inside, \(\frac{4x^{2}y^{-3}}{2x^{-1}y}=2x^{3}y^{-4}\), and raising to (-2) gives \(\frac{y^{8}}{4x^{6}}\). In exams, simplify inside the bracket first.अंदर \(\frac{4x^{2}y^{-3}}{2x^{-1}y}=2x^{3}y^{-4}\), इसलिए घात (-2) देने पर \(\frac{y^{8}}{4x^{6}}\) मिलता है। परीक्षा में पहले कोष्ठक के अंदर सरल करें।
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