(\frac{\(a^{2}b^{-1}\)^{-3}}{a^{-4}b^{2}}) का सरल रूप क्या है?
What is the simplified form of (\frac{\(a^{2}b^{-1}\)^{-3}}{a^{-4}b^{2}})?
Explanation opens after your attempt
A. \(a^{-2}b\)
Concept
(\(a^{2}b^{-1}\)^{-3}=a^{-6}b^{3}), then \(\frac{a^{-6}b^{3}}{a^{-4}b^{2}}=a^{-2}b\). In exams, subtract powers of the same base during division.
Why this answer is correct
The correct answer is A. \(a^{-2}b\). (\(a^{2}b^{-1}\)^{-3}=a^{-6}b^{3}), then \(\frac{a^{-6}b^{3}}{a^{-4}b^{2}}=a^{-2}b\). In exams, subtract powers of the same base during division.
Exam Tip
(\(a^{2}b^{-1}\)^{-3}=a^{-6}b^{3}), फिर \(\frac{a^{-6}b^{3}}{a^{-4}b^{2}}=a^{-2}b\)। परीक्षा में भाग करते समय समान आधार की घात घटाएं।
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