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If roots of (x^2-16x+48=0) are (\alpha,\beta), which equation has roots (\alpha+6,\beta+6)?

Answer and explanation

Correct answer: (x^2-28x+180=0)

The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.

Related tags

QuadraticTransformed-RootsEquationMethods Of Solving Quadratic EquationsQuadratic EquationsMathematicsClass 10 Mcq

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