यदि \(x^2-16x+48=0\) के मूल \(\alpha,\beta\) हैं, तो नए मूल \(\alpha+6,\beta+6\) वाला समीकरण कौनसा है?

If roots of \(x^2-16x+48=0\) are \(\alpha,\beta\), which equation has roots \(\alpha+6,\beta+6\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-28x+180=0\)

Step 1

Concept

The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-28x+180=0\). The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.

Step 3

Exam Tip

मूल (4,12) हैं, इसलिए नए मूल (10,18) होंगे और समीकरण ((x-10)(x-18)=0) है। परीक्षा में नए मूल बनाकर नया समीकरण लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-16x+48=0\) के मूल \(\alpha,\beta\) हैं, तो नए मूल \(\alpha+6,\beta+6\) वाला समीकरण कौनसा है? / If roots of \(x^2-16x+48=0\) are \(\alpha,\beta\), which equation has roots \(\alpha+6,\beta+6\)?

Correct Answer: A. \(x^2-28x+180=0\). Explanation: मूल (4,12) हैं, इसलिए नए मूल (10,18) होंगे और समीकरण ((x-10)(x-18)=0) है। परीक्षा में नए मूल बनाकर नया समीकरण लिखें। / The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.

Which concept should I revise for this Mathematics MCQ?

The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.

What exam hint can help solve this Mathematics question?

मूल (4,12) हैं, इसलिए नए मूल (10,18) होंगे और समीकरण ((x-10)(x-18)=0) है। परीक्षा में नए मूल बनाकर नया समीकरण लिखें।