यदि \(x^2-16x+48=0\) के मूल \(\alpha,\beta\) हैं, तो नए मूल \(\alpha+6,\beta+6\) वाला समीकरण कौनसा है?
If roots of \(x^2-16x+48=0\) are \(\alpha,\beta\), which equation has roots \(\alpha+6,\beta+6\)?
Explanation opens after your attempt
A. \(x^2-28x+180=0\)
Concept
The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.
Why this answer is correct
The correct answer is A. \(x^2-28x+180=0\). The roots are (4,12), so new roots are (10,18), and the equation is ((x-10)(x-18)=0). In exams, form the new roots and then the new equation.
Exam Tip
मूल (4,12) हैं, इसलिए नए मूल (10,18) होंगे और समीकरण ((x-10)(x-18)=0) है। परीक्षा में नए मूल बनाकर नया समीकरण लिखें।
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