यदि \(\alpha,\beta\) समीकरण \(3x^2-11x+6=0\) के मूल हैं, तो \(\alpha\beta\) क्या है?
If \(\alpha,\beta\) are roots of \(3x^2-11x+6=0\), what is \(\alpha\beta\)?
Explanation opens after your attempt
Correct Answer
A. (2)
Concept
The product of roots is \(\frac{c}{a}=\frac{6}{3}=2\). In exams, use \(\frac{c}{a}\) for the product.
Why this answer is correct
The correct answer is A. (2). The product of roots is \(\frac{c}{a}=\frac{6}{3}=2\). In exams, use \(\frac{c}{a}\) for the product.
Exam Tip
मूलों का गुणनफल \(\frac{c}{a}=\frac{6}{3}=2\) है। परीक्षा में गुणनफल के लिए \(\frac{c}{a}\) का प्रयोग करें।
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