यदि \(\alpha,\beta\) समीकरण \(3x^2-11x+6=0\) के मूल हैं, तो \(\alpha+\beta\) क्या है?
If \(\alpha,\beta\) are roots of \(3x^2-11x+6=0\), what is \(\alpha+\beta\)?
Explanation opens after your attempt
Correct Answer
A. \( \frac{11}{3}\)
Concept
The sum of roots is \(-\frac{b}{a}=-\frac{-11}{3}=\frac{11}{3}\). In exams, keep the sign of (b) carefully.
Why this answer is correct
The correct answer is A. \( \frac{11}{3}\). The sum of roots is \(-\frac{b}{a}=-\frac{-11}{3}=\frac{11}{3}\). In exams, keep the sign of (b) carefully.
Exam Tip
मूलों का योग \(-\frac{b}{a}=-\frac{-11}{3}=\frac{11}{3}\) है। परीक्षा में (b) का चिन्ह ध्यान से रखें।
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