यदि (a=3) है तो \(a^2+a^{-1}\) का मान क्या है?
If (a=3), what is the value of \(a^2+a^{-1}\)?
Explanation opens after your attempt
Correct Answer
B. \(\frac{28}{3}\)
Concept
\(3^2=9\) and \(3^{-1}=\frac{1}{3}\). Thus the sum is \(9+\frac{1}{3}=\frac{28}{3}\).
Why this answer is correct
The correct answer is B. \(\frac{28}{3}\). \(3^2=9\) and \(3^{-1}=\frac{1}{3}\). Thus the sum is \(9+\frac{1}{3}=\frac{28}{3}\).
Exam Tip
\(3^2=9\) और \(3^{-1}=\frac{1}{3}\) है। इसलिए योग \(9+\frac{1}{3}=\frac{28}{3}\) है।
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