समीकरण (5x-10y=20) और (x-2y=4) के ग्राफ कैसे होंगे?

How will the graphs of (5x-10y=20) and (x-2y=4) be?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

Dividing the first equation by (5) gives (x-2y=4). Therefore the two lines have infinitely many common points.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. Dividing the first equation by (5) gives (x-2y=4). Therefore the two lines have infinitely many common points.

Step 3

Exam Tip

पहला समीकरण (5) से भाग देने पर (x-2y=4) बनता है। इसलिए दोनों रेखाओं के अनंत सामान्य बिंदु हैं।

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समीकरण (5x-10y=20) और (x-2y=4) के ग्राफ कैसे होंगे? / How will the graphs of (5x-10y=20) and (x-2y=4) be?

Correct Answer: C. संपाती / Coincident. Explanation: पहला समीकरण (5) से भाग देने पर (x-2y=4) बनता है। इसलिए दोनों रेखाओं के अनंत सामान्य बिंदु हैं। / Dividing the first equation by (5) gives (x-2y=4). Therefore the two lines have infinitely many common points.

Which concept should I revise for this Mathematics MCQ?

Dividing the first equation by (5) gives (x-2y=4). Therefore the two lines have infinitely many common points.

What exam hint can help solve this Mathematics question?

पहला समीकरण (5) से भाग देने पर (x-2y=4) बनता है। इसलिए दोनों रेखाओं के अनंत सामान्य बिंदु हैं।