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An item sold for \(x\) rupees generates a total revenue of \(x(70-x)\) rupees. If the total revenue is 1200 rupees, what is the larger value of \(x\)?

Answer and explanation

Correct answer: 40

We have \(x(70-x)=1200\). Rearranging gives \(x^2-70x+1200=0\), which factors as \((x-30)(x-40)=0\). Thus, \(x=30\) or \(x=40\), and the larger value is 40. Exam tip: In such problems, form the quadratic equation first, find both roots, and then select the one requested.

Related tags

Quadratic-EquationsWord-ProblemsRevenueWord Problems And ApplicationsQuadratic EquationsMathematicsClass 10 Mcq

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