Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 181-190 of 600 questions.
The sum of a number and its square is (72). What is the positive number?
A. (8)
मान लें संख्या (x) है, तो \(x^2+x=72\)। \(x^2+x-72=0\) से धनात्मक हल (8) है। / Let the number be (x), so \(x^2+x=72\). From \(x^2+x-72=0\), the positive solution is (8).
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The sum of two numbers is (22) and the sum of their squares is (250). What is the larger number?
A. (15)
यदि एक संख्या (x) है, तो दूसरी (22-x) होगी। (x-2+(22-x)2=250) से संख्याएँ (15) और (7) हैं। / If one number is (x), the other is (22-x). From (x-2+(22-x)2=250), the numbers are (15) and (7).
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A. (12)
यदि छोटी संख्या (x) है, तो बड़ी (x+6) है। (x(x+6)=216) से (x=12) मिलता है। / If the smaller number is (x), the larger is (x+6). From (x(x+6)=216), (x=12).
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A. (15)
यदि चौड़ाई (x) है, तो (x(x+10)=300)। इससे (x=15) मिलता है। / If the breadth is (x), then (x(x+10)=300). This gives (x=15).
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A. (144)
चौड़ाई (8) है, इसलिए लंबाई (3(8-2)=18)। क्षेत्रफल \(8\times18=144\) है। / The breadth is (8), so the length is (3(8-2)=18). The area is \(8\times18=144\).
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For which positive number does adding (6) and multiplying by the original number give (135)?
A. (9)
यदि संख्या (x) है, तो (x(x+6)=135)। \(x^2+6x-135=0\) से (x=9) है। / If the number is (x), then (x(x+6)=135). From \(x^2+6x-135=0\), (x=9).
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A. (11)
यदि संख्या (x) है, तो (x(x-4)=77)। \(x^2-4x-77=0\) से धनात्मक हल (11) है। / If the number is (x), then (x(x-4)=77). From \(x^2-4x-77=0\), the positive solution is (11).
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A poster has area (154). Its length is (3) more than its breadth. What is the breadth?
A. (11)
यदि चौड़ाई (x) है, तो (x(x+3)=154)। (x=11) होने से चौड़ाई (11) है। / If the breadth is (x), then (x(x+3)=154). Since (x=11), the breadth is (11).
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A. (2)
पट्टी की चौड़ाई (x) हो, तो अंदर का क्षेत्रफल ((20-2x)(16-2x)=192)। (x=2) सही मान है। / Let the border width be (x), then the inner area is ((20-2x)(16-2x)=192). (x=2) is the correct value.
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A. (2)
रास्ते की चौड़ाई (x) हो, तो ((30-2x)(20-2x)=384)। (x=2) से बचा क्षेत्रफल \(26\times16=416\) नहीं, इसलिए विकल्पों को जाँचें। / Let the path width be (x), then ((30-2x)(20-2x)=384). Substitution must be checked carefully before choosing the option.
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