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If the line 4x + ay = 20 is coincident with the line 2x + 3y = 10, what is the value of a?यदि रेखा 4x + ay = 20, रेखा 2x + 3y = 10 के संपाती हो, तो a का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 66
Coincident lines have equations that are nonzero multiples of each other. Multiplying 2x + 3y = 10 by 2 gives 4x + 6y = 20, which must match 4x + ay = 20. Therefore, a = 6, so option A is correct.संपाती रेखाओं के समीकरण एक-दूसरे के अशून्य गुणज होते हैं। 2x + 3y = 10 को 2 से गुणा करने पर 4x + 6y = 20 मिलता है। इसे 4x + ay = 20 से मिलाने पर a = 6 मिलता है, इसलिए विकल्प A सही है।
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