यदि \(x=\sqrt{3}+\sqrt{2}\), तो \(\frac{1}{x}\) का परिमेय हर वाला रूप कौन-सा है?
If \(x=\sqrt{3}+\sqrt{2}\), which is the rationalized form of \(\frac{1}{x}\)?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{3}-\sqrt{2}\)
Concept
The conjugate of \(\sqrt{3}+\sqrt{2}\) is \(\sqrt{3}-\sqrt{2}\).
Why this answer is correct
The denominator becomes (3-2=1), so \(\frac{1}{\sqrt{3}+\sqrt{2}}=\sqrt{3}-\sqrt{2}\).
Exam Tip
When the difference of the squared surds is (1), the result becomes very simple. चरण 1: \(\sqrt{3}+\sqrt{2}\) का संयुग्मी \(\sqrt{3}-\sqrt{2}\) है। चरण 2: हर (3-2=1) बनता है, इसलिए \(\frac{1}{\sqrt{3}+\sqrt{2}}=\sqrt{3}-\sqrt{2}\)। चरण 3: जिन दो मूलों के वर्गों का अंतर (1) हो, वहाँ उत्तर बहुत सरल आता है।
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