यदि \(a=\sqrt{3}+\sqrt{2}\) और \(b=\sqrt{3}-\sqrt{2}\), तो \(\frac{a-b}{a+b}\) का मान क्या है?
If \(a=\sqrt{3}+\sqrt{2}\) and \(b=\sqrt{3}-\sqrt{2}\), what is the value of \(\frac{a-b}{a+b}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{\sqrt{6}}{3}\)
Concept
\(a-b=2\sqrt{2}\) and \(a+b=2\sqrt{3}\).
Why this answer is correct
\(\frac{a-b}{a+b}=\frac{\sqrt{2}}{\sqrt{3}}=\frac{\sqrt{6}}{3}\).
Exam Tip
Do not forget to rationalize the denominator at the end. चरण 1: \(a-b=2\sqrt{2}\) और \(a+b=2\sqrt{3}\)। चरण 2: \(\frac{a-b}{a+b}=\frac{\sqrt{2}}{\sqrt{3}}=\frac{\sqrt{6}}{3}\)। चरण 3: अंत में हर को परिमेय बनाना न भूलें।
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