Concept-wise Practice

squaring algebra MCQ Questions for Class 10

squaring algebra se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with squaring algebra.

Question 1/3 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

\(\sqrt{2}\) के प्रमाण में (p=2k) रखने के बाद \(p^2\) किसके बराबर होगा?

In the proof of \(\sqrt{2}\), after putting (p=2k), what is \(p^2\) equal to?

Explanation opens after your attempt
Correct Answer

A. \(4k^2\)

Step 1

Concept

(p=2k).

Step 2

Why this answer is correct

Squaring gives (p-2=(2k)2=4k-2).

Step 3

Exam Tip

Writing ((2k)2) as \(2k^2\) is a common mistake. चरण 1: (p=2k) है। चरण 2: दोनों ओर वर्ग करने पर (p-2=(2k)2=4k-2)। चरण 3: ((2k)2) को \(2k^2\) लिखना आम गलती है।

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Question 2/3 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

\(\sqrt{5}\) के प्रमाण में (p=5k) रखने के बाद \(p^2\) किसके बराबर होगा?

In the proof of \(\sqrt{5}\), after putting (p=5k), what is \(p^2\) equal to?

Explanation opens after your attempt
Correct Answer

A. \(25k^2\)

Step 1

Concept

We have (p=5k).

Step 2

Why this answer is correct

Squaring gives (p-2=(5k)2=25k-2).

Step 3

Exam Tip

Do this simplification carefully in the proof of \(\sqrt{5}\). चरण 1: (p=5k) दिया है। चरण 2: वर्ग करने पर (p-2=(5k)2=25k-2)। चरण 3: \(\sqrt{5}\) के प्रमाण में यह सरलीकरण ध्यान से करें।

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Question 3/3 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

\(\sqrt{3}\) के प्रमाण में (p=3k) रखने के बाद \(p^2\) किसके बराबर होगा?

In the proof of \(\sqrt{3}\), after putting (p=3k), what is \(p^2\) equal to?

Explanation opens after your attempt
Correct Answer

A. \(9k^2\)

Step 1

Concept

(p=3k).

Step 2

Why this answer is correct

Squaring gives (p-2=(3k)2=9k-2).

Step 3

Exam Tip

Do not forget to square the coefficient also. चरण 1: (p=3k) है। चरण 2: वर्ग करने पर (p-2=(3k)2=9k-2)। चरण 3: गुणांक का भी वर्ग करना न भूलें।

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