Concept-wise Practice

sector-arc MCQ Questions for Class 11

sector-arc se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with sector-arc.

यदि चाप (s=22) सेमी और त्रिज्यखंड क्षेत्रफल (A=121) वर्ग सेमी है तो केंद्र कोण रेडियन में क्या है?

If arc (s=22) cm and sector area (A=121) square cm, what is the central angle in radians?

Explanation opens after your attempt
Correct Answer

B. (2) रेडियन(2) radians

Step 1

Concept

Using \(A=\frac{1}{2}rs\), \(121=\frac{1}{2}r\cdot22\), so (r=11) and \( \theta=\frac{s}{r}=2 \). When arc and area are given, find (r) first.

Step 2

Why this answer is correct

The correct answer is B. (2) रेडियन / (2) radians. Using \(A=\frac{1}{2}rs\), \(121=\frac{1}{2}r\cdot22\), so (r=11) and \( \theta=\frac{s}{r}=2 \). When arc and area are given, find (r) first.

Step 3

Exam Tip

\(A=\frac{1}{2}rs\) से \(121=\frac{1}{2}r\cdot22\) इसलिए (r=11) और \( \theta=\frac{s}{r}=2 \) है। चाप और क्षेत्रफल साथ दिए हों तो पहले (r) निकालें।

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यदि चाप की लंबाई (20) सेमी और त्रिज्यखंड क्षेत्रफल (150) वर्ग सेमी है तो त्रिज्या क्या है?

If arc length is (20) cm and sector area is (150) square cm, what is the radius?

Explanation opens after your attempt
Correct Answer

C. (15) सेमी(15) cm

Step 1

Concept

Sector area is \( \frac{1}{2}rs \), so \(150=\frac{1}{2}\times r\times20\) gives (r=15). When arc length is given, \( \frac{1}{2}rs \) is useful.

Step 2

Why this answer is correct

The correct answer is C. (15) सेमी / (15) cm. Sector area is \( \frac{1}{2}rs \), so \(150=\frac{1}{2}\times r\times20\) gives (r=15). When arc length is given, \( \frac{1}{2}rs \) is useful.

Step 3

Exam Tip

त्रिज्यखंड क्षेत्रफल \( \frac{1}{2}rs \) है इसलिए \(150=\frac{1}{2}\times r\times20\) से (r=15) है। चाप दिया हो तो \( \frac{1}{2}rs \) उपयोगी है।

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यदि चाप की लंबाई (16) सेमी और त्रिज्यखंड क्षेत्रफल (64) वर्ग सेमी है तो त्रिज्या क्या है?

If arc length is (16) cm and sector area is (64) square cm, what is the radius?

Explanation opens after your attempt
Correct Answer

C. (8) सेमी(8) cm

Step 1

Concept

Sector area is \( \frac{1}{2}rs \), so \(64=\frac{1}{2}\times r\times16\) gives (r=8). When arc length is given, \( \frac{1}{2}rs \) is very useful.

Step 2

Why this answer is correct

The correct answer is C. (8) सेमी / (8) cm. Sector area is \( \frac{1}{2}rs \), so \(64=\frac{1}{2}\times r\times16\) gives (r=8). When arc length is given, \( \frac{1}{2}rs \) is very useful.

Step 3

Exam Tip

त्रिज्यखंड क्षेत्रफल \( \frac{1}{2}rs \) है इसलिए \(64=\frac{1}{2}\times r\times16\) से (r=8) है। चाप दिया हो तो \( \frac{1}{2}rs \) बहुत उपयोगी है।

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