यदि \(x^2+px+42=0\) के मूल (-6) और (-7) हैं, तो (p) क्या है?
If the roots of \(x^2+px+42=0\) are (-6) and (-7), what is (p)?
Explanation opens after your attempt
A. (13)
Concept
((x+6)(x+7)=x-2+13x+42), so (p=13). In exams, form factors from given roots.
Why this answer is correct
The correct answer is A. (13). ((x+6)(x+7)=x-2+13x+42), so (p=13). In exams, form factors from given roots.
Exam Tip
((x+6)(x+7)=x-2+13x+42), इसलिए (p=13) है। परीक्षा में दिए मूलों से गुणनखंड बनाएं।
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