quotient-simplification se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
3 questions tagged with quotient-simplification.
A. (x+2), \(x\ne -1\)
(\frac{x-2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2), पर \(x\ne -1\)। हर के शून्य मान को हटाना जरूरी है। / (\frac{x-2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2), but \(x\ne -1\). It is necessary to exclude the zero of the denominator.
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If (f(x)=x-2-3x+2) and (g(x)=x-1), what is the correct form of (\left\(\frac{f}{g}\right\)(x))?
A. \(x-2,\ x\ne 1\)
(x-2-3x+2=(x-1)(x-2)), पर (x=1) हटेगा। सरलीकृत रूप के साथ प्रांत प्रतिबंध लिखना जरूरी है। / (x-2-3x+2=(x-1)(x-2)), but (x=1) is excluded. Always write the domain restriction with a simplified form.
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If (f(x)=x-2-2x) and (g(x)=x-2), what is the simplified form of (\left\(\frac{f}{g}\right\)(x))?
A. \(x,\ x\neq 2\)
(\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), पर \(x\neq 2\)। cancelled factor से मूल restriction खत्म नहीं होती। / (\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), but \(x\neq 2\). A cancelled factor does not remove the original restriction.
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