\(\frac{x^2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2\), पर \(x\ne -1\)। हर के शून्य मान को हटाना जरूरी है। / \(\frac{x^2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2\), but \(x\ne -1\). It is necessary to exclude the zero of the denominator.
Mathematics Answer, Explanation and Revision Hints
यदि \(f(x)=x^2+3x+2\) और \(g(x)=x+1\) हैं तो \(\left(\frac{f}{g}\right)(x)\) का सरल रूप क्या है? / If \(f(x)=x^2+3x+2\) and \(g(x)=x+1\) then what is the simplified form of \(\left(\frac{f}{g}\right)(x)\)?
Correct Answer: A. (x+2), \(x\ne -1\). Explanation: \(\frac{x^2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2\), पर \(x\ne -1\)। हर के शून्य मान को हटाना जरूरी है। / \(\frac{x^2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2\), but \(x\ne -1\). It is necessary to exclude the zero of the denominator.
Login to view answers
Use Google login or mobile OTP. Admin can block users and control login providers.
Privacy preferences
Hum essential cookies/session ka use login, class selection aur security ke liye karte hain. Analytics, marketing aur personalized ads optional hain.
