यदि (f(x)=x-2+3x+2) और (g(x)=x+1) हैं तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप क्या है?
If (f(x)=x-2+3x+2) and (g(x)=x+1) then what is the simplified form of (\left\(\frac{f}{g}\right\)(x))?
Explanation opens after your attempt
Correct Answer
A. (x+2), \(x\ne -1\)
Concept
(\frac{x-2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2), but \(x\ne -1\). It is necessary to exclude the zero of the denominator.
Why this answer is correct
The correct answer is A. (x+2), \(x\ne -1\). (\frac{x-2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2), but \(x\ne -1\). It is necessary to exclude the zero of the denominator.
Exam Tip
(\frac{x-2+3x+2}{x+1}=\frac{(x+1)(x+2)}{x+1}=x+2), पर \(x\ne -1\)। हर के शून्य मान को हटाना जरूरी है।
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